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Alchen [17]
3 years ago
7

What is 1/10 of 1 3.027

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0

Answer:

1.3027

Step-by-step explanation:

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dalvyx [7]
In your point, y is 3 and x is 2.  You have to fill in these values for x and y into each equation in A-D to see which one is "true".  Let's start with A.  y = -3x.  Filling in 3 for y and 2 for x gives us 3 = -3(2).  Does 3 equal -6?  Of course not.  So let's try B.  y = x - 1.  3 = 2 - 1.  Does 3 = 1?  Of course not!  Let's try C.  y = 3x...3 = 3(2).  3 doesn't equal 6 either, so...last one.  y = x + 1 is 3=2+1.  Does 3 = 3?  Yes!  Finally! So the point on the coordinate plane is one the line represented by D.
3 0
3 years ago
Solve the equation 12x+6y= 24 for x.
velikii [3]

Answer: x = -1/2y + 2

Step-by-step explanation:

12x + 6y = 24  To solve for x  first start by subtracting 6y from both sides

      - 6y    -6y

12x =  24 - 6y    Now divide each side by 12

x= 2 - 1/2y

7 0
3 years ago
Read 2 more answers
Solve for 2/3(9 - 6) + 40<br> and 7/8 - (-1/10) + (-3/5)
masha68 [24]

Answer:

first one is 42

second one is 3/8

Step-by-step explanation:

4 0
3 years ago
5. Put the following numbers in order from least to greatest in the spaces provided.
zloy xaker [14]

Answer:

7,7.5,8,8.1

Step-by-step explanation:

count 1 to 10. See what comes first and that's how you determine what comes first.

5 0
3 years ago
Cindy shoots a bottle rocket straight up into the air such that its height h, in feet, at time t, in seconds, is given by the fu
dezoksy [38]

Answer:

t = [0.493,4.2]

Step-by-step explanation:

The height of the rocket straight up into the air is given by :

h(t)=-16t^2+85t+5

We need to find the interval the rocket be at least 43 feet above the ground.

43\ge -16t^2+85t+5\\\\t\ge 0.493\ and\ t\le 4.82\ s

So, the required interval during which the rocket is at least 43 feet above the ground is [0.493,4.2].

6 0
3 years ago
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