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lisabon 2012 [21]
3 years ago
13

4. The spiral development model combines iterative development with the methods of the waterfall model.

Computers and Technology
1 answer:
rodikova [14]3 years ago
4 0

Answer:

true

Explanation:

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11)When, if ever, will the geometric average return exceed the arithmetic average return for a given set of returns?A) When the
grigory [225]

Answer: E. Never

geometric average return can NEVER exceed the arithmetic average return for a given set of returns

Explanation:

The arithmetic average return is always higher than the other average return measure called the geometric average return. The arithmetic return ignores the compounding effect and order of returns and it is misleading when the investment returns are volatile.

Arithmetic returns are the everyday calculation of the average. You take the series of returns (in this case, annual figures), add them up, and then divide the total by the number of returns in the series. Geometric returns (also called compound returns) involve slightly more complicated maths.

6 0
3 years ago
Propose a data structure that supports the stack push and pop operations and a third operation findMin, which returns the smalle
juin [17]

Answer: attached below

Explanation:

3 0
3 years ago
In one week, your company received the following quantities of e-mail messages. Monday 240 Tuesday 315 Wednesday 290 Thursday 18
Vika [28.1K]

Answer:

280

Explanation:

Average = (240 + 315 + 290 + 180 + 375) ÷ 5

= 1400 ÷ 5

= 280

Cheers

3 0
3 years ago
What are the steps to apply new layout to the slide. ( Write in easy way)​
pogonyaev

Answer:

Explanation:

Apply a slide layout

1 . Select the slide that you want to change the layout for.

2 . Select Home > Layout.

3 . Select the layout that you want. The layouts contain placeholders for text, videos, pictures, charts, shapes, clip art, a background, and more. The layouts also contain the formatting for those objects, like theme colors, fonts, and effects

5 0
3 years ago
A computer program is tested by 5 independent tests. If there is an error, these tests will discover it with probabilities 0.1,
Svetllana [295]

Answer:

0.8488

Explanation:

Let E =error found by test 1

Let F=error found by test 2

Let G=error found by test 3

Let H=error found by test 4

Let I= error found by test 5

Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5

therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5

Tests are independent P(not E & not F &not G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512

P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488

5 0
4 years ago
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