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3 years ago

Name two different numbers that round to 30 when rounded to the nearest ten

Mathematics

2 answers:

andrew11 [14]3 years ago

6 0

For this case we have the following definition:

tens place: number of two digits whose absolute value is greater than zero.

Then, we have the following rounding rule:

If the previous number is greater than or equal to five, the next number increases by one unit.

We then have the following numbers rounded to 30 when rounded to the nearest ten:

26: twenty-six

27: twenty-seven

Answer:

two different numbers that round to 30 when rounded to the nearest ten are:

26: twenty-six

27: twenty-seven

SVETLANKA909090 [29]3 years ago

5 0

Any thing above 25 and below 35.
25, 26, 27, 28, 29, 30, 31, 32, 33, 34

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Write down the possible values of x.x is an interger.

Simora [160]

Answer:

-1, 0, 1, 2, 3

Step-by-step explanation:

To answer this you have to understand 2 main things

These are: the symbols and what an integer is.

An integer is simply a whole number. For example: 1, 10, 3 etc.

The symbols, <= (first symbol) and < (second symbol) are very important. These tell us the range X is in.

<= means less than or equal to.

< means less than.

So we can write: -1 is less than or equal to x and x is less than 4.

If we follow this and also keep in mind we only want whole numbers then we can see the lowest X can be is -1 and the highest it can be is 3 since it has to be less than 4.

Then it is also everything inbetween them which is:

-1, 0, 1, 2, 3

5 0

3 years ago

Is the answer to (-1)^2-(-2-(9-1)), <br><br> 11?

yulyashka [42]

Answer: Yes that's correct

Work Shown:

(-1)^2-(-2-(9-1))

1-(-2-(8))

1-(-2-8)

1-(-10)

1 + 10

Note that (-1)^2 = (-1)*(-1) = 1, and subtracting a negative turns into a positive.

3 0

1 year ago

The annual net income of a company for the period 2007–2011 could be approximated by P(t) = 1.6t2 − 11t + 44 billion dollars (2

son4ous [18]

Answer:

$P'(t) = 3.2 t -11$

And we can set equal this derivate to 0 in order to find the critical point and we got:

$3.2 t-11= 0$

$t = \frac{11}{3.2}= 3.4375$

And we can calculate the second derivate and we got:

$P''(t) = 3.2 >0$

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

$P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094$

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094

Step-by-step explanation:

For this case we have the following function:

$P(t) = 1.6 t^2 -11t +44$

Where P represent the annual net income for the period 2007-2011 and $2 \leq t \leq 7$

And t represent the time in years since the start of 2005

In order to find the lowet income we need to use the derivate, given by:

$P'(t) = 3.2 t -11$

And we can set equal this derivate to 0 in order to find the critical point and we got:

$3.2 t-11= 0$

$t = \frac{11}{3.2}= 3.4375$

And we can calculate the second derivate and we got:

$P''(t) = 3.2 >0$

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

$P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094$

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094

5 0

3 years ago

Write and simplify an expression that represents the perimeter of the parallelogram.

UkoKoshka [18]

8x+=10 and 6x+4= 11 hope this helps

6 0

3 years ago

For the function y=3x−1, when the input (x)= 7, the output (y) = ?

MariettaO [177]

Answer:

y=3x-1 (replace x with 7 )

Step-by-step explanation:

y=3 (7)-1

y= 21-1

y= 20

note: multiply 3 with seven and minus 1 the answer is y so y=20

8 0

2 years ago