The computation illustrated shows that the numbers that can be used to get the sum of 42 will be 12 and 15.
<h3>How to compute the value?</h3>
It should be noted that the puzzle simply involves algebraic thinking. The goal is to find numbers that can be added together that will give 42.
From the information, it should be noted that 7 and 8 have been given. Therefore, this will be:
= 42 - (7 + 8)
= 42 - 15
= 27
Therefore, the numbers that can give 27 can be put in the box. An example is 12 and 15.
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Answer: Thus, the number with the larger value of 8 is 184.36 and it is 100 times larger.
Step-by-step explanation:
First we can find out the place value,
Then we can write,
Define Place value :
Place value is the basis of our entire number system. This is the system in which the position of a digit in a number determines its value. The number 42,316 is different from 61,432 because the digits are in different positions.
[or]
Place value of a digit can be defined as the position of the particular digit in a given number.
For Example :
The place value of 7 in 1870 is 70
Given the data,
First we use digit is : 184.36
Second we use digit is : 9027.83
Place value of 8 in First digit is ⇒ 184.36 is 80
Place value of 8 in Second digit is ⇒ 9027.83 is 0. 8
We can solve the Ratio is :
Ratio = 80/ 0.8
Ratio = 100 times
Therefore,
Thus, the number with the larger value of 8 is 184.36 and it is 100 times larger.
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Let
<span>A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)
step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm
step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm
step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm
step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm
step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD
step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and
AB and AD are perpendicular
BC and CD are perpendicular
therefore
the shape is a square wit length side √18 cm
area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²
the answer is18 cm²see the attached figure
Answer:Triangle A: 38 degrees
Triangle B: Unknown (not enough information)
Triangle C: Unknown (not enough information)
Triangle D: 70 degrees
Triangle E: 40 degrees
Step-by-step explanation: