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Sever21 [200]
3 years ago
9

A metal washer has an outer diameter of 14mm and an inner diameter of 6mm.Use the value of 3.14 for the to find the area of the

metal washer
Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

502.4 mm^2

Step-by-step explanation:

First find the area of the larger circle, and then that of the smaller one.

Then subtract the latter (2nd) area from the first.

larger circle area           smaller circle area

-------------------------           ---------------------------

 3.14(14 mm)^2                   3.14(6 mm)^ 2

This comes out to 3.14[14^2 - 6^2] mm^ 2 =  3.14[196 - 36] mm^2, or

3.14(160 mm^2) = 502.4 mm^2

The area of the metal washer is 502.4 mm^2.

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Answer:

4. No

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8. No

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9b. 90 : 36 = 135 : 54 Extremes: 90, 54. Means: 36, 135

Step-by-step explanation:

4. 12 : 25 and 6 : 13 are NOT equal. NO.

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6 0
3 years ago
Jonathan records how 90 pupils travelled to school on one day and represents this information on the pie chart below.
xeze [42]

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86.4

Step-by-step explanation:

First adding up all the percentages on the chart you get 360

Then figuring out what 24° of 360 is

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4 0
2 years ago
A museum worker randomly displays 5 historical writings in a row. What is the probability that the worker lines them up from the
Mars2501 [29]

The number of ways to arrange the 5 writings in a row is 5! = 5 * 4 * 3 * 2 * 1 = 120 ways.

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4 0
3 years ago
Determine the length of the longest metal rod which could be stored in a rectangle box 20 cm by 50 cm by 30 cm.
navik [9.2K]

Answer:

61.64 cm

Step-by-step explanation:

The longest metal rod which could be stored in a rectangular box will be equal to its diagonal:

\therefore \: length \: of \:metal \: rod  \\  =  \sqrt{ {l}^{2} +  {b}^{2}   +  {h}^{2} }  \\  =  \sqrt{ {20}^{2} +  {50}^{2}  +  {30}^{2}  }  \\  =  \sqrt{400 + 2500 + 900}  \\  =  \sqrt{3800}  \\  = 61.64414 \\  = 61.64 \: cm

5 0
3 years ago
Read 2 more answers
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