Answer:radius = diameter/2=12/2=6cm...
area of semicircle = πr^2/2
={3.14×(2)^2}/2
=6.28cm^2.......
Step-by-step explanation:
PEMDAS
1. Parenthesis first
5 + 2 = 7
2. Exponents
7^2 = 49
49 = 49
Hope that helps!!!
The correct answer is B. I figured this out by testing out coordinates into each equation. I am only going to show my work for equation B though... if you want to see the rest of my work, message me.
(0,0) ⇒ this point is within the shaded part of the graph
0 ≤ 1/2(0) + 3
0 ≤ 0 + 3
0 ≤ 3
True
(1,4) ⇒ this point is within the unshaded region
4 ≤ 1/2(1) + 3
4 ≤ 1/2 + 3
4 ≤ 3.5
False
This proves that equation B matches the graph shown.
a) Due to you have a right triangle, in order to calculate the value of d, use the Pythagorean thorem:
![d=\sqrt[]{(60m)^2+(20m)^2}=\sqrt[]{4000m^2}\approx63.2m](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%2860m%29%5E2%2B%2820m%29%5E2%7D%3D%5Csqrt%5B%5D%7B4000m%5E2%7D%5Capprox63.2m)
Hence, the distance d is approximately 63.2m
b) To find the angle of elevation, use the sine function of θ, as follow:
Hence, the angle of elevation is approximately 19.8°
