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Alik [6]
3 years ago
12

What is the missing term in the geometric sequence?

Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0
Is a geometric sequence, so that means a number is multiplying to current term to get the next one... meaning if we simply divide those two terms, the quotient is that "multiplier", namely the "common ratio"

so... hmm let's try say -1536 and 384

\bf \cfrac{-1536}{384}\implies -4\impliedby \textit{common ratio}
\\\\\\
n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
n=n^{th}\ term\\
----------\\
a_1=-6\\
r=-4\\
n=3
\end{cases}
\\\\\\
\textit{the third term is then }\implies a_3=(-6)(-4)^{3-1}
\\\\\\
a_2=(-6)(-4)^2\implies a_2=-6\cdot 16\implies a_2=-96

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We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
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Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

<h3>Given information-</h3>

The given function is,

h(x)=x^2+1

k(x)=x-2

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

(h+k)(x)=h(x)+k(x)

(h+k)(x)=x^2+1+x-2

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(h+k)(x)=5

2)The value of the function (h-k)(3),

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(h-k)(x)=9

3) The value of the function 3h(2)+2k(3)

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3h(2)+2k(3)=17

Hence the value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

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brainly.com/question/2263981

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