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2 years ago

Tyson wrote this expression to describe the total amount of points he won in both rounds of a game.

1 answer:

7 0

We know that Tyson wrote this expression to describe the total amount of points he won in both rounds of a game.

The expression is f+15. Let variable f represent points.

The correct answer is B. Tyson doesn't know how many points he earned in the first round. He knows he earned a total of 15 points in the whole game.

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The Coffee Spot served several pastries this afternoon.

AlladinOne [14]

Answer:

the answer is 4

Step-by-step explanation:

I did the homework

7 0

2 years ago

Value of x 9(2x-1)-9x - 18

bixtya [17]

Let's simplify step-by-step.9(2x−1)−9x−18

Distribute:=(9)(2x)+(9)(−1)+−9x+−18=18x+−9+−9x+−18

Combine Like Terms:=18x+−9+−9x+−18=(18x+−9x)+(−9+−18)=9x+−27

Answer:=9x−27

5 0

2 years ago

Read 2 more answers

$1200 is invested at 3% compounded quarterly. What is the total amount, to the nearest dollar, after 5 years?

Mekhanik [1.2K]

The formula to calculate the amount is 1200(1+0.03/4)^5

8 0

3 years ago

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago

Jeff has a box containing 26 tiles, each with a different letter of the alphabet. he randomly draws 4 letters, one at a time wit

MArishka [77]

The probability to choose letter n is $\frac{1}{26}$ . After drawing letter n there left 25 letters and the probability to choose the letter w is $\frac{1}{25}$ . After drawing two letters n and w there left 24 letters and then the probability to choose letter b is $\frac{1}{24}$ . After drawing three letters n, w and b there left 23 letters, so the probability to choose letter t is $\frac{1}{23}$ .
Using the product rule for probabilities, you can obtain that $P= \frac{1}{26} * \frac{1}{25} * \frac{1}{24}* \frac{1}{23} =0.0000027$ .

8 0

2 years ago