Question

S = 1 / g t ² π, solve for t​

Answer 1

$s = \frac{1}{g {t}^{2}\pi }$

multiply through by

$g {t}^{2} \pi$

$s \times g {t}^{2} \pi = \frac{1}{g {t}^{2} \pi} \times g {t}^{2} \pi$

$sg {t}^{2} \pi = 1$

dividing through by

sgπ

${t}^{2} = \frac{1}{sg\pi}$

$t = \sqrt{ \frac{1}{sg\pi} }$

Answer 2

$\bf S=\cfrac{1}{2}gt^2\pi \implies S = \cfrac{gt^2\pi }{2}\implies 2S=gt^2\pi \implies \cfrac{2S}{g\pi }=t^2\implies \sqrt{\cfrac{2S}{g\pi }}=t$