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3 years ago

5

Daria has 18 coins that are all nickels and quarters. the number of nickels is 3 more than twice the number of quarters. if she

has $1.90 in all, how many nickels does Daria have?

1 answer:

sergij07 [2.7K]3 years ago

3 0

Daria has 12 to 15 nickels because 3x3=9 but u want to double the amount which would be 12 to 15

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Question: When you do adding fractions, do you have to find a common demoniter? *sorry for misspelling*

docker41 [41]

Answer: yes when your adding or subtracting fractions you must find the common denominator between the two before you continue.

Step-by-step explanation:

Example: 2/4+3/2

Find the common denominator. ( in this case the common denominator is 4)

We keep the first fraction as it is cause it has the denominator 4 and we multiply the second fraction by 2 up and down to get a denominator of 4. The equation becomes 2/4+6/4

Now you add the numerators and you got your answer ( don’t forget to simplify)

The answer after adding in this case is 8/4 and when simplified it is 2

5 0

3 years ago

If we sample from a small finite population without replacement, the binomial distribution should not be used because the event

seropon [69]

Answer:

5/4324 = 0.001156337

Step-by-step explanation:

To better understand the hyper-geometric distribution consider the following example:

There are 100 senators in the US Congress, and suppose 60 of them are republicans so 100 - 60 = 40 are democrats).

We extract a random sample of 30 senators and we want to answer this question:

What is the probability that 10 senators in the sample are republicans (and of course, 30 - 10 = 20 democrats)?

The answer using the h-g distribution is:

$\large \frac{\binom{60}{10}\binom{100-60}{30-10}}{\binom{100}{30}}=\frac{\binom{60}{10}\binom{40}{20}}{\binom{100}{30}}$

Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).

<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be

$\large \frac{\binom{6}{4}\binom{56-6}{6-4}}{\binom{56}{6}}=\frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}$

Now compute each combination separately:

$\large \binom{6}{4}=\frac{6!}{4!2!}=15\\\\\binom{50}{2}=\frac{50!}{2!48!}=1225\\\\\binom{50}{6}=\frac{50!}{6!44!}=15890700$

and now replace the values:

$\large \frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}=\frac{15*1225}{15890700}=\frac{18375}{15890700}=\frac{5}{4324}$

and that is it.

If the decimal expression is preferred then divide the fractions to get 0.001156337

6 0

3 years ago

I need help with this

Natali [406]

I’m pretty sure this is correct.

8 0

3 years ago

Evaluate the following expression: 082

Sauron [17]

This for points.

Nanskw

7 0

2 years ago

Which fraction does not belong with the other three explain 1/12 2/12 3/12 or 4/12

MakcuM [25]

1/12 does not belong with the other three fractions.

2/12, 3/12, and 4/12 can all be simplified to 1/6, 1/4/, and 1/3. However, 1/12 can't be simplified.

6 0

3 years ago