If someone answers this correctly Ill be there friend

Mathematics

2 answers:

TEA [102]3 years ago

7 0

Answer:

The answer is C

Step-by-step explanation:

Because it's going over 3 & up 1. Since it's rise over run it would be 1/3.

Alex17521 [72]3 years ago

4 0

Answer should be c..

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945 round nearest ten

Pavlova-9 [17]

945 rounded to the nearest ten is 950

7 0

3 years ago

Read 2 more answers

on the grid, which point is located in the quadrant where the x-coordinate is a negative number and the y- coordinate is a posit

lina2011 [118]

Answer:

Step-by-step explanation:

because if you look at it the x-coordinate is -6 and the y-coordinate is positive 4

8 0

3 years ago

Find the sum of the first four terms of the geometric sequence shown below. 4, 4/ 3, 4/9, ...

user100 [1]

It's evident that the first four terms are 4, 4/3, 4/9, and 4/27. So the fourth partial sum of the series is

$S_4=4+\dfrac43+\dfrac49+\dfrac4{27}$

It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.

Multiply the sum by 1/3 and you have

$\dfrac13S_4=\dfrac43+\dfrac49+\dfrac4{27}+\dfrac4{81}$

Now subtracting this from $S_4$ gives

$S_4-\dfrac13S_4=4-\dfrac4{81}$

That is, all the matching terms will cancel. Now solving for $S_4$ , you
have

$\dfrac23S_4=4\left(1-\dfrac1{81}\right)$
$S_4=6\left(1-\dfrac1{81}\right)$
$S_4=\dfrac{480}{81}=\dfrac{160}{27}$

3 0

3 years ago

IQ scores are measured with a test designed so that the mean is 116 and the standard deviation is 16. Consider the group of IQ s

butalik [34]

Answer:

So the z-scores that separate the unusual IQ scores from those that are usual are Z = -2 and Z = 2.

The IQ scores that separate the unusual IQ scores from those that are usual are 84 and 148.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 116, \sigma = 16$