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Charra [1.4K]
3 years ago
13

If someone answers this correctly Ill be there friend

Mathematics
2 answers:
TEA [102]3 years ago
7 0

Answer:

The answer is C

Step-by-step explanation:

Because it's going over 3 & up 1. Since it's rise over run it would be 1/3.

Alex17521 [72]3 years ago
4 0
Answer should be c..
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Help me please I don’t know how to
Irina-Kira [14]

Answer:

A: 22

Step-by-step explanation:

2The interquartile range begins at 45 and ends at 67. All you need to do is subtract 45 drom 67, and you get 22.

4 0
2 years ago
Please help me with both questions!!!!​​
Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a  dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0
3 years ago
What’s the solution to the system 5y=6x-4 and 3y=-6x+20
Elina [12.6K]

Answer:

6x-5y=4

6x+3y=30

Step-by-step explanation:

Move variable to the left

5y=6x-4

Reorder the terms

5y-6x=-4

Change the signs

-6x+5y=-4

Move variable to the left

3y=-6x+20

Reorder the terms

3y+6x=20

3 0
3 years ago
Find the distance between the points (1, 5) and (1, -4).
Ganezh [65]

Answer:

9

Step-by-step explanation:

\tt distance=\sqrt{(1-1)^2+(-4-5)^2}=\sqrt{0^2+9^{2}}=\sqrt{9^2} =9

6 0
3 years ago
Read 2 more answers
DOES ANYONE UNDERTAND THIS? IF SO PLEASE HELP
Nana76 [90]
The sides must be equal otherwise BC and AD wouldn't be parallel.  So
12x-6 = 2x+7 
10x = 13
x = 13/10 = 1.3

8 0
3 years ago
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