Answer:
If the question does not limit man to produce only one model of club, then the maximized profit of every condition produced under 50 sets daily will be all model A exclusive. such as $60 x 50 (model A) , even just produce 49 set that day, the maximal profit is still $60 x 49.
Step-by-step explanation:
If the question does not limit man to produce only one model of club, then the maximized profit of every condition produced under 50 sets daily will be all model A exclusive. such as $60 x 50 (model A) , even just produce 49 set that day, the maximal profit is still $60 x 49.
Re-consider the logic of the question ....
Let the number be x.
Therefore, by the problem
x/6-(-3) = 12
or, x/6+3 = 12
or, x/6 = 12-3
or, x/6 = 9
or, x = 9 × 6
or, x = 54
The number is 54.
Factor x^4-y^4: (x²+y²)(x²-y²)
further factor: (x²+y²)(x+y)(x-y)
so the dimensions are (x²+y²)(length), (x+y) (width), and (x-y) (height)
The difference between the mean of the sample and the mean of the population is A. 0.55
<h3>Calculations and Parameters:</h3>
Given the population data is:
0 3 3 1 3 2 2 2 5 4 3 3 3 0 1 2 0 2 3 3
The sample data is:
5 3 0 2 4
The mean of the population data is:
45/20= 2.25
The mean of the sample data is:
14/5= 2.8
Therefore, the difference between the mean of the sample and the population is:
2.8-2.25= 0.55
Read more about mean here:
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Answer:
5 to 3
Step-by-step explanation:
