A deck of cards contains 6 black cards and 6 red cards. The first card drawn is not replaced before drawing the second card.
1 answer:
Answer : 5/22
A deck of cards contains 6 black cards and 6 red cards. The first card drawn is not replaced before drawing the second card.
Total number of outcome of cards = 12
Probability( any event)= favorable outcomes divide by total number of outcomes
Probability of selecting black card =
The drawn card is not replaced . so 11 cards left . In that 11 cards, 5 black cards because one black card is already chosen
Probability of selecting another black card =
Probability of selecting a black card followed by another black card =
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Answer:
The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.
Step-by-step explanation:
Given:
Coin is tossed and a single 6 sided number cube is rolled.
Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.
Now, we know that:
Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes
Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.
So, probability of event 'H' is given as:
Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is,
Now, probability of rolling a 3 is given as:
Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,
Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.
Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.