Answer:
A
Step-by-step explanation:
16+3:19
11+8:19
19=19
A) It says in fraction form. y=5/4x +15
b) it says it should be a decimal. If you extend the line, it will reach 15.5 hours.
c) I think your answer was correct
Answer:
1
Step-by-step explanation:
Probability = number of fruit type/total number of fruit. Total number of fruit = 5 + 9 + 5 = 19.
The probability of drawing an apple is P(apple) = number of apples/total number of fruit = 5/19.
The probability of drawing a peach is P(peach) = number of peaches/total number of fruit = 9/19
The probability of drawing an apple is P(orange) = number of oranges/total number of fruit = 5/19
The probability of drawing either an apple, peach or orange at the first draw of fruit from the bag is
P(apple or peach or orange) = P(apple) + P(peach) + P(orange)
= 5/19 + 9/19 + 5/19
= (5 + 9 + 5)/19
= 19/19
= 1
Answer:it’s B (120 succes and 80 failures for khan academy)
Step-by-step explanation: trust me
Answer:
- Exact distance =
feet - Approximate distance = 127.2792 feet.
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Explanation:
The area of the square is 8100 square feet, abbreviated ft^2.
Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.
If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).
Use the pythagorean theorem to find the hypotenuse.
![a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\](https://tex.z-dn.net/?f=a%5E2%20%2B%20b%5E2%20%3D%20c%5E2%5C%5C%5C%5Cc%20%3D%20%5Csqrt%7Ba%5E2%2Bb%5E2%7D%5C%5C%5C%5Cc%20%3D%20%5Csqrt%7B90%5E2%2B90%5E2%7D%5C%5C%5C%5Cc%20%3D%20%5Csqrt%7B2%2A90%5E2%7D%5C%5C%5C%5Cc%20%3D%20%5Csqrt%7B2%7D%2A%5Csqrt%7B90%5E2%7D%5C%5C%5C%5Cc%20%3D%20%5Csqrt%7B2%7D%2A90%5C%5C%5C%5Cc%20%3D%2090%5Csqrt%7B2%7D%20%5C%20%5Ctext%7B%20...%20exact%20distance%7D%5C%5C%5C%5Cc%20%5Capprox%20127.2792%20%5C%20%5Ctext%7B%20...%20approximate%20distance%7D%5C%5C%5C%5C)
The distance from 1st to 3rd base is roughly 127.2792 feet.