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Archy [21]
3 years ago
12

Kelly has saved $35 to take music classes. She must pay a registration fee of $15 and then an additional $5 for each class. Whic

h equation will best help Kelly determine the number of classes she can afford?
15c - 5 = 35
15c - 5 = 35

5c - 15 = 35
5c - 15 = 35

5c + 15 = 35
5c + 15 = 35

15c + 5 = 35
15c + 5 = 35
Mathematics
2 answers:
KonstantinChe [14]3 years ago
7 0

Answer:its the last choice

Step-by-step explanation: im sorry if i get this wrong lol

Alex Ar [27]3 years ago
5 0

Answer:  

I would think 15c+5= 35 because it is the one answer that makes the most sense.  If you get this wrong I am so sorry.

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Jana And Jordan had 23 oranges Jana had 7 fewer oranges than Jordan how many oranges did each girl have
Solnce55 [7]

Answer:

Jana had 8 oranges, and Jordan had 15 oranges.

Step-by-step explanation:

First, identify what you know:

1) In total, Jana and Jordan had 23 oranges.

2) Jana had 7 less oranges than Jordan.

We can create a formula, where x equals the number of oranges Jana has.

23 = x + (x + 7)

16 = x + x (subtracted 7 from both sides)

x = 8 (divided both sides by 2)

So, now we know Jana had 8 oranges, which is 7 less than Jordan.

8 + 7 = ?

? = 15

Jana had 8 oranges, while Jordan had 15, for a total of 23 oranges.

3 0
3 years ago
can someone please help how did i get this wrong . the question says wich of the following could be used to estimate quotient 34
schepotkina [342]

Answer:

3500÷6= 583

Step-by-step explanation:

It is 3500, because 5, the tens can give 4, the hundred

3 0
2 years ago
What is (3.1 times 10 Superscript 5 Baseline) (2.2 times 10 Superscript 7 Baseline) in scientific notation? 5.5 times 10 Supersc
aev [14]

Answer:

(B) 6.82 times 10 Superscript 12

Step-by-step explanation:

I just took the quiz

8 0
3 years ago
Read 2 more answers
Kam
I am Lyosha [343]

Answer:Im pretty sure it's 25% percent loss

Step-by-step explanation:

sorry if im wrong

6 0
3 years ago
Help me please fast ​
Natalija [7]

Answer:

Step-by-step explanation:

\frac{5}{x-3}+\frac{2}{x+1}=3  \\\\\frac{5(x+1)+2(x-3)}{(x-3)(x+1)} =3\\\\5x+5+2x-6=3(x-3)(x+1)\\\\7x-1=3(x^2+x-3x-3)\\\\7x-1=3(x^2-2x-3)\\\\7x-1=3x^2-6x-9\\\\0=3x^2-6x-7x-9+1\\0=3x^2-13x-8

Hence proved!

3 0
3 years ago
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