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frutty [35]
3 years ago
5

An equilateral triangle has an altitude of 12.84 m. What is the length of the three equal sides?

Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

14.83m

Step-by-step explanation:

In an equilateral triangle, of side l and altitude h we have:

h=l/2×sqrt(3).

l=2h/sqrt(3)=2×12.84/1.73=14.83m

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Please help me I’m so lost !!!!
Tasya [4]

Answer:

4095

Step-by-step explanation:

\sum _{n=1}^63\left(4^{n-1}\right)\:

\sum _{n=1}^63\cdot \:4^{n-1}

Compute general progression:

\frac{3\cdot \:4^{\left(n+1\right)-1}}{3\cdot \:4^{n-1}}=4

r=4\\

a_1=3\cdot \:4^{1-1}

a_1=3

nth term is computed by:

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5 0
3 years ago
Use the zero product property to find the solutions to the equation x2 – 15x – 100 = 0.
IrinaK [193]

Answer:

x= 20      x =-5

Step-by-step explanation:

x^2 – 15x – 100 = 0.

What two numbers multiply to -100 and add to -15

-20 * 5 = -100

-20 +5 = -15

(x-20) (x+5) =0

Using the zero product property

x-20 =0     x+5 = 0

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7 0
3 years ago
Read 2 more answers
Please please help me!!!! :)
kifflom [539]

Answer:

Measure of ∠5 is 142°

Step-by-step explanation:

We are given that, Lines L and M are parallel.

As, the third line is intersecting both line L and M.

<em>We know that, 'The opposite angles formed by the intersecting lines are equal'.</em>

Since, the sum of the four angles formed by the third line and M is 360°.

So, we get,

∠1 + ∠6 + ∠7 + 38 = 360°

i.e. 2∠1 + 2×38°  = 360°

i.e. 2∠1 = 360° - 76°

i.e. 2∠1 = 284°

i.e. ∠1 = 142°

Thus, ∠1 = ∠7 = 142°

Since, L and M are parallel.

So, ∠3 = ∠5 = 142°

Hence, we get that measure of ∠5 is 142°.

3 0
3 years ago
What is a reasonable estimate for the problem? 3 3/4 x -2/5
Airida [17]

Answer:

You can not break that down any further if x does not equal anything and the equation is not equal to anything.

Step-by-step explanation:

6 0
3 years ago
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