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slava [35]
3 years ago
11

Is -19.3 a integer??

Mathematics
1 answer:
Amanda [17]3 years ago
3 0

its not an integer because they have to be positive or negative whole numbers. hope this helps  

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What is the distance ?
Gwar [14]

Distance between 2 points formula: √(x2 − x1)² + (y2 − y1)²

= √(7 - (-3))² + (-1 - 5)²

= √10² + -6²

= √100 + 36

= √136

≈ 11.662 (Note that this number is rounded because its a a non-terminating decimal).

Best of Luck!

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It would be 10 the slope is always with the x
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Answer to 42.7 -(-12.4)
Aleks [24]
<span>42.7−<span>(<span>−12.4</span>)

</span></span><span>=<span>42.7−<span>(<span>−12.4</span>)

</span></span></span><span>=<span>42.7+12.4

</span></span><span>=<span>55.1</span></span>
4 0
3 years ago
Points (-1,2), (-4,7), (-3,1), (-2,4) lie in ______ quadrant
dalvyx [7]

Answer:

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5 0
2 years ago
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
2 years ago
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