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stepladder [879]
3 years ago
7

Factorize the question which is (2x + xy-y) + 2x - y

Mathematics
1 answer:
BigorU [14]3 years ago
3 0

Answer:

4x+xy−2y is your answer.

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Someone please tell me what to do
kifflom [539]
For this, we need to find the area of the larger rectangle (The room) and subtract from that the area of the smaller, shaded rectangle (The rug).
A=LW (L=Length, W=Width, A=Area)

The larger rectangle first:
A=(15)(10)
A=150 feet squared

Now the Rug:
A=(12)(7)
A=84 feet squared

Now to find the area that is NOT covered by the rug, we subtract:
150-84
= 66 feet squared will NOT be covered by the rug.

Hope this Helps!
-Sinnamin
4 0
4 years ago
14.7 divided by 2.2=
GenaCL600 [577]

Answer:

6.68181818182

Step-by-step explanation:

3 0
3 years ago
I will give extra points please help
kotegsom [21]

Answer:

z is less than 3/4

Step-by-step explanation:

7 0
3 years ago
Kite WXYZ is graphed on a coordinate plane. What is the area of the kite?
Misha Larkins [42]

Answer:

14 square units

Step-by-step explanation:

There are several ways we can find the area.  Probably the easiest is to cut the kite in half vertically and find the area of each triangle.  The area of the kite will be double that.

The height of the kite is 7 units, and the width is 4 units.  So each triangle will have a base of 7 and height of 2.

A = 1/2 bh

A = 1/2 (7) (2)

A = 7

The area of the kite is double that, so:

2A = 14

3 0
3 years ago
Read 2 more answers
What is -9x-(2x/-3) When x equals 7
yuradex [85]
-9x- \frac{2x}{-3}

-9*(7) -  \frac{2*7}{-3}

9*7 = 63

\frac{2*7}{-3}  =  \frac{14}{-3}

Apply the fraction  rule : \frac{a}{-b} = -  \frac{a}{b}

= - \frac{14}{3}

-63-( -\frac{14}{3} )

Apply rule  - ( - a) = a

-63+ \frac{14}{3}

Convert  element to fraction :

63 =  \frac{63}{1}

-\frac{63}{1} + \frac{14}{3}

Find the LCD 1*3 = 3

- \frac{63*3}{3}+ \frac{14}{3}

\frac{-3+63+14}{3} =  \frac{-175}{3}

<span>Apply the fraction  rule : \frac{a}{-b} = - \frac{a}{b}</span>

= - \frac{175}{3}

hope this helps!

4 0
3 years ago
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