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siniylev [52]
3 years ago
8

Find two points on the line to be graphed. y-5=0

Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0
Any point with the y of 5 could be the answer
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Can someone please help me and show work too. If you can thank you
djyliett [7]

Answer:

3n-7

Step-by-step explanation:

8 0
2 years ago
the product of two whole numbers is 36 . what is the greatest possible sum that the number can have?​
ch4aika [34]

Whole numbers are positive numbers without decimals.  First, list all the whole number factors of 36:

1 and 36

2 and 18

3 and 12

4 and 9

6 and 6

Next, see which one of those pairs has the highest sum:

1+36=37

2+18=20

3+12=15

4+9=13

6+6=12

The greatest possible sum the numbers can have is 37.

Hope this helps!!

3 0
2 years ago
564 which statement is false? It is the sum of 56 tens and 4 ones. The number of hundreds is more than the number of tens. To ge
nirvana33 [79]

Answer:

The number of hundreds is more than the number of tens.

Step-by-step explanation:

The sum of 56 tens and 4 ones= 560 + 4 (true)

The number of hundreds is more than the number of tens.

Number of hundreds = 5

Number of tens = 56

5 is not greater than 56.

7 0
3 years ago
Which is the graph of the linear equation y = –one-fourthx + 3?
Aleksandr-060686 [28]

Step-by-step explanation:

need the graph

but, it will cross y axis at 3 and line will be going down

7 0
3 years ago
Find the interquartile range of the data.
likoan [24]

The answer is 14. Here is how I work it out.


First we are going have to identify quartile 1 and quartile 3.


So after putting the numbers in order from least to greatest mark the number with a half way point.

This is optional but it will help us spot the sections better.


31,33,35,41,43,|46,48,49,49,50

Next put parentheses around the remaining groups of numbers.

(31,33,35,41,43,)|(46,48,49,49,50)


For the next step we have to find the median of each group.


(31,33,35,41,43,)|(46,48,49,49,50)


The median of each group, are called the quartiles, the median of the lower half is quartile 1, and the median of the upper half is quartile 3.


Now subtract quartile 1 from quartile 3.


49 – 35 = 14


So the interquartile range of this data set is 14.

4 0
3 years ago
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