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AlekseyPX
3 years ago
8

WILL GIVE BRAINLIEST

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0
Translation, rotation, and reflection are always congruent. Dilation's are similar to each other....
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The square root of 54 is what??
Vikentia [17]
\sqrt{54} = 7.348469228

this is irrational, because it cannot be written in the form \frac{a}{b}
2. Irrational
6 0
3 years ago
What is the value of log Subscript 6 Baseline StartFraction 1 Over 36 EndFraction?
loris [4]

Answer:

-2

Step-by-step explanation:

Let  x be the unknown value  

Log₆  ( 1/36) = x

( 1/36) = 36⁻¹ = (6²)⁻¹ = 6⁻²

Log₆  ( 1/36) = Log₆ 6⁻²  = -2 Log₆ 6

Log₆ 6 = 1

-2 Log₆ 6 = -2(1) = -2

4 0
3 years ago
Read 2 more answers
I just need to check if I'm right. For 9 and 10
Arlecino [84]
9 and 10 are correct :)
5 0
3 years ago
Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
Arada [10]

Answer:

a) 0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

b) n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

c) n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

\hat p=\frac{823}{1000}=0.823

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

Part c

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

5 0
3 years ago
Multiplying Polynomials write in standard form <br> (x+3)(x+4)
ankoles [38]

Answer:

x² + 7x + 12

Step-by-step explanation:

1. (x +3)(x+4)      - Distribute

2. x² + 4x +3x + 12   - Add like terms

3. x² +7x + 12

5 0
3 years ago
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