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3 years ago

Write an equation that gives the proportional relationship of the graph.

Mathematics

1 answer:

melomori [17]3 years ago

4 0

<h3>Answer:</h3>

C) y = 6x

<h3>Step-by-step explanation:</h3>

Pick any point. It is often convenient to use x = 1 (no marked point) or x = 10 (where y = 60).

Use these values to see which equation agrees.

A: 60 ≠ (1/6)·10

B: 60 ≠ 2·20

C: 60 = 6·10

D: 60 ≠ 12·10

____

Or, you can solve ...

... y = kx

for k, using the point values you found on the graph.

... 60 = k·10

... 60/10 = k = 6 . . . . . divide by 10

This makes the equation be ...

... y = 6x . . . . . . matches selection C

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Is this correct not sure

Digiron [165]

Answer:

which didi you pick , but if you pitted the sixeth one is correct

Step-by-step explanation:

because I hope this helps

4 0

2 years ago

The proportion of defective computers built by Byte Computer Corporation is 0.15. In an attempt to lower the defective rate, the

FinnZ [79.3K]

Answer:

a) Null hypothesis : H₀: the proportion of defective item of computer has been lowered. That is P < 0.15

Alternative hypothesis: H₁: The proportion of defective item of computer

has been higher. That is P> 0.15 (Right tailed test)

b) Test statistic $Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }$

c) Calculate the value of the test statistic = 0.991

d) The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57

e) Null hypothesis accepted at 0.01 level of significance

f) we accepted null hypothesis.

Hence the proportion of defective item of computer has been lowered.

Step-by-step explanation:

Step(i):-

Given the sample size 'n' = 42

Given random sample of 42 computers were tested revealing a total of 4 defective computers.

The defective computers 'x' = 4

The sample proportion of defective computers

$p = \frac{x}{n} = \frac{4}{42} = 0.095$

Given The Population proportion 'P' = 0.15

The level of significance ∝=0.01

Step(ii):-

a) Null hypothesis : H₀: the proportion of defective item of computer has been lowered. That is P < 0.15

Alternative hypothesis: H₁: The proportion of defective item of computer

has been higher. That is P> 0.15 (Right tailed test)

Test statistic $Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }$

$Z = \frac{0.095-0.15}{\sqrt{\frac{0.15(0.85)}{42} } }$

$z = \frac{-0.055}{\sqrt{0.00303} } = - 0.9991$

Calculate the value of the test statistic Z = - 0.9991

|Z| = |- 0.9991| = 0.991

Step(iii):-

The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57

e) Calculate the value of the test statistic Z = 0.991 < 2.57 at 0.01 level of significance.

Conclusion:-

Hence the null hypothesis is accepted at 0.01 level of significance.

The proportion of defective item of computer has been lowered.

6 0

3 years ago

P=−4b 2 +6b−9 Q=7b 2 −2b−5 P−Q= Your answer should be a polynomial in standard form.

shepuryov [24]

Answer:

−11b^2+8b−4

Step-by-step explanation:

−4b2+6b−9−7b2+2b+5

Simplify by adding terms.

11b2+8b−4

3 0

3 years ago

Jan spent $48 for 5 movie tickets. Three kids’ tickets were $8 each. How much were the 2 adult tickets. Write an equation to mod

JulijaS [17]

Answer:

t=$20 for each two adults

Step-by-step explanation:

$48-8=$40

$40×2=$20

8 0

3 years ago

Which of the following is the solution to 31 %-12 12?

stellarik [79]

Answer:

I think so, but don't lose sight

4 0

3 years ago