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musickatia [10]
3 years ago
6

1. An ecosystem consists of one oak tree on which 10,000 herbivores are feeding. These herbivores are prey to 500 spiders and ca

rnivorous insects. There birds of the same species are eating these spiders and carnivorous insects. The oak tree has a mass of 4000 kg, the herbivores insects have an average mass of 0.05 g, the spiders and carnivorous insects have an average mass of 0.2 g and the three birds have an average mass of 10 g.
a. Construct, to scale, a pyramid of numbers.
b. Construct, to scale, a pyramid of biomass.
c. Explain the differences between these two pyramids.
Biology
1 answer:
PIT_PIT [208]3 years ago
7 0
A) Scale: 1 mm² = 1 organism
The base of the pyramid will be a square that is 1 mm by 1 mm
The next tier of herbivores will be 100 mm by 100 mm
The next tier of carnivorous insects and spiders will be 50 mm by 10 mm
The final tier of birds will be 3 mm by 1 mm

b) Biomasses:
Tree = 4000 kg
Herbivores = 10,000 x 0.05/1000 = 0.5 kg
Carnivores = 500 x 0.2/1000 = 0.1 kg
Birds = 3 x 10/1000 = 0.03 kg
Scale: 1 mm² = 0.1 kg
The bottom tier will be 400 mm by 100 mm
The next tier will be 5 mm by 1 mm
The next tier will be 1 mm by 1 mm
The final tier will be 0.3 mm by 0.1 mm

The pyramid of numbers and pyramid of biomass are the opposites of one another because energy is lost as we go up the tiers of a food pyramid. Only 10% of the energy in a trophic level is passed to a higher one. This is why the overall numbers may increase, due to smaller organisms, but the main place where organisms utilize energy, production of biomass, reduces drastically.
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A breeder is trying to decrease the maturation time in a population of sunflowers. In this population, the mean time to flowerin
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Answer:

The next generation average time to flowering will be 98 days.

Explanation:

Before answering the question, we need to know a few concepts.

  • Artificial selection is the selecting practice of a specific group of organisms in a population -that carry the traits of interest- to be the parents of the following generations.  
  • Parental individuals carrying phenotypic values of interest are selected from the whole population. These parents interbreed, and a new generation is produced.  
  • The selection differential, SD, is the difference between the mean value of the trait in the population (X₀) and the mean value of the parents, (Xs). So,  

SD = Xs - X₀

  • Heritability in the narrow-sense, h², is the genetic component measure to which additive genetic variance contributes. The heritability might be used to determine how the population will respond to the selection done, R.  

h² = R/SD

  • The response to selection (R) refers to the metric value gained or lost from the cross between the selected parents. R can be calculated by multiplying the heritability h², with the selection differential, SD.  

R = h²SD  

R also equals the difference between the new generation phenotypic value (X₁) and the original population phenotypic value (X₀),  

R = X₀ - X₁

-------------------------------------------------------------------------------------------------------------

Now that we know these concepts and how to calculate them, we can solve the proposed problem.

<u>Available data:  </u>

  • trying to decrease the maturation time in a population of sunflowers.
  • the population mean time to flower is 100 days → X₀
  • Chosen parental Plants mean flowering time is 90 days → Xs
  • the narrow-sense heritability for flowering time is 0.2 → h²

According to what we sow previously, we need to find out the value of X₁, which reflects the next generation average time to flowering.

  • We know that R = X₁ - X₀, so we need to clear this formula to calculate X₁

X₁ = R + X₀

We already know that X₀ = 100 days,  

Now we need to calculate R.  

  • R = h²SD

We know that h² = 0.2,  

Now we need to calculate SD

  • SD = Xs - X₀

Xs = 90 days → Parentals media flowering time

X₀ = 100 → Population media flowering time

SD = Xs - X₀  

SD = 90 - 100  

SD = - 10 days

Knowing this, we can calculate R

  • R = h²SD

o h² = 0.2  

o SD = - 10

R = 0.2 x (-10)

R = - 2

  • Finally, once we know the R-value we can calculate the X₁ value

X₁ = R + X₀

X₁ = - 2 + 100

X₁ = 98

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