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zhuklara [117]
2 years ago
9

In a titration, 10.0 ml of 0.0750 M HCl(aq) is exactly neutralized by 30.0 ml of KOH(aq) of unknown concentration. What is the c

oncentration of the KOH(aq)solution?
Chemistry
1 answer:
Sphinxa [80]2 years ago
4 0

Answer: 0.0250

Explanation: 10 X 0.0750 = .75

.75 / 30 = 0.0250 M

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One molecule

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Calculate the average atomic mass for element X
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39.02amu

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According to this question, there are four (4) isotopes for element X with the following relative abundance:

Isotope 1 = 9.67%, mass no: 38

Isotope 2 = 78.68%, mass no: 39

Isotope 3 = 11.34%, mass no: 40

Isotope 4 = 0.31%, mass no: 41

To find the average atomic mass of element X, we multiply each isotopes' relative abundance by its mass no and find the sum as follows:

We convert each percentage to decimal abundance:

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(0.0967 × 38) + (0.7868 × 39) + (0.1134 × 40) + (0.0031 × 41)

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