South carolinians feared that the hire terrace of 1828 would cause
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Answer:
The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme
Explanation:
From the given information:
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.
In this same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;
Rate factor in the absence of catalyst:
Rate factor in the presence of catalyst:
Assuming the catalyzed reaction and the uncatalyzed reaction are taking place at the same temperature :
Then;
the ratio of the rate factors can be expressed as:
Thus;
Let say the assumed temperature = 25° C
= (25+ 273)K
= 298 K
Then ;
The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme
C: 0.012 mol.
<h3>Explanation</h3>Start with 0.0020 moles of iodate ions .
How many moles of iodine will be produced?
converts to
in the first reaction. The coefficient in front of
is three times the coefficient in front of
. In other words, each mole of
will produce three moles of
. 0.0020 moles of
will convert to 0.0060 moles of
.
How many moles of thiosulfate ions are required?
reacts with
in the second reaction. The coefficient in front of
is twice the coefficient in front of
. How many moles of
does each mole of
consume? Two. 0.0060 moles of
will be produced. As a result,
moles of
will be needed.