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4 years ago

Consider the balanced chemical equation for the combustion of methane (CH4).

Chemistry

2 answers:

Mrac [35]4 years ago

5 0

<h3>Answer:</h3>

89.6 L of O₂

<h3>Solution:</h3>

The balanced chemical equation is as,

CH₄ + 2 O₂ → CO₂ + 2 H₂O

As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,

44 g ( 1 mol) CO₂ is produced by = 44.8 L (2 mol) of O₂

So,

88 g CO₂ will be produced by = X L of O₂

Solving for X,

X = (88 g × 44.8 L) ÷ 44 g

X = 89.6 L of O₂

KIM [24]4 years ago

3 0

Took a guess and got it right!

D) 89.6 L

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25cc of 5 % NaOH solution neutralized 30cc of h2sO4 solution. Whatis normality of H2SO4?

MAVERICK [17]

The normality of the H₂SO₄ that reacted with 25cc of 5 % NaOH solution is 1.1 N.

<h3>What is the molarity of 5% NaOH?</h3>

The molarity of 5% NaOH is 1.32 M

25 cc of NaOH neutralized 30cc of H₂SO₄ solution.

Equation of reaction is given below:

2 NaOH + H₂SO₄ ---> Na₂SO₄ + 2 H₂O

Molarity of H₂SO₄ = 1.32 x 1 x 25/(30 x 2) = 0.55 M

Normality = Molarity × moles of H⁺ ions per mole of acid

moles of H⁺ ions per mole of H₂SO₄ = 2

Normality of H₂SO₄ = 0.55 x 2 = 1.1 N

In conclusion, the normality of an acid is determined from the molarity and the moles of H⁺ ions per mole of acid.

Learn more about normality at: brainly.com/question/22817773

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jenyasd209 [6]

Animals might have to change their courtship behavior due to climate change.

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3 years ago

Ethyl alcohol (ch3ch2oh) is/is not soluble in water. 1. is; all organic molecules are soluble in water. 2. is; ethyl alcohol exh

nata0808 [166]

Answer:
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Explanation:
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4 years ago

How is a hydrate different from other chemical compounds?

babunello [35]

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4 years ago

We add excess NaCl solution (58.44 g/mol) to 72 mL of a solution of silver nitrate (AgNO3 169.88 g/mol), to form insoluble solid

Andre45 [30]

Answer:

The molarity of the original AgNO3 solution is 0.2529 M

Explanation:

<u>Step 1:</u> The balanced equation

AgNO3 + NaCL → AgCl + NaNO3

This means that for 1 mole of AgNO3 consumed, 1 mole of NaCL will be consumed, to produce 1 mole of AgCL and 1 mole of NaNO3

<u>Step 2</u>: Calculating moles of AgCl

Moles of AgCl = mass of AgCL / Molar mass of AgCL

moles of AgCl = 2.61 grams / 143.32g/mole

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<u>Step 3:</u> Calculating moles of AgNO3

Since there is consumed 1 mole of AgNO3 to produce 1 mole of AgCl, this means that if there is produced 0.01821 moles of AgCl, there is consumed also 0.01821 moles of AgNO3

<u>Step 4:</u> Calculating molarity of AgNO3

Molarity of AgNO3 = moles of AgNO3 / volume of AgNO3

Molarity of AgNO3 = 0.01821 moles/ 0.072 L = 0.2529 M = 0.2529 mol/L

The molarity of the original AgNO3 solution is 0.2529 M

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4 years ago