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Tanya [424]
3 years ago
5

Consider the balanced chemical equation for the combustion of methane (CH4).

Chemistry
2 answers:
Mrac [35]3 years ago
5 0
<h3>Answer:</h3>

                  89.6 L of O₂

<h3>Solution:</h3>

The balanced chemical equation is as,

                                CH₄  +  2 O₂    →    CO₂  +  2 H₂O

As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,

             44 g ( 1 mol) CO₂ is produced by  =  44.8 L (2 mol) of O₂

So,

                  88 g CO₂ will be produced by  = X L of O₂

Solving for X,

                        X = (88 g × 44.8 L) ÷ 44 g

                        X = 89.6 L of O₂

KIM [24]3 years ago
3 0
Took a guess and got it right!

D) 89.6 L
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Difference between proton and electron​
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Answer:

An electron is a negatively charged component of an atom

the proton is a positively charged body.

Explanation:

3 0
3 years ago
What is the value of the activation energy of the uncatalyzed reaction?
Lubov Fominskaja [6]
The value of the activation energy of an uncatalyzed reaction is greater than that of a catalyzed reaction. As we know, a catalyst provides an alternative path for the reaction to happen at a faster rate. So, for a catalyzed reactio, activation energy is lesser than the original path.
6 0
3 years ago
A compound is 54.53% c, 9.15% h, and 36.32% o by mass. what is its empirical formula? the molecular mass of the compound is 132
Yakvenalex [24]
 <span>First - you need the empirical formula. 

So, assume you have 100 g of the compound. 

If so, you'll have 54.53 gram of C, 9.15 g of H and 36.32 g of O. Find the number of moles of each. 

54.53 g C (1 mole C / 12.01 g C) = 4.540 

9.15 g H (1 mole H / 1.008 g H) = 9.077 

36.32 g O (1 mole O / 15.9994 g O) = 2.270 

Take the smallest number found and divide the others by it to get the empirical formula. 

4.540/2.270 = 2. 
9.077/2.270 = 4. 
2.270/2.270 =1. 

So, that gives you the empirical formula of C2H4O. 

Find the weight of this compound. C = 12, H = 1, O = 16. So, C2H4O is 44 amu. 

132/44 = 3. 

So, 3 (C2 H4 O) = C6H12O3 = molecular formula.</span>
6 0
3 years ago
Which trend is observed as the first four elements in group 17 on the periodic table are considered in order of increasing atomi
ExtremeBDS [4]

ANSWER:

The melting and boiling points increase in order of increasing atomic number.

The size of the nucleus increases in order of increasing atomic number.

Ionization energy decreases in order of increasing atomic number.

Electronegativity decreases in order of increasing atomic number.

Electron Affinity decreases in order of increasing atomic number.

The reactivities decrease in order of increasing atomic number.

EXPLANATION:

NAME     MELTING POINT    BOILING POINT

Fluorine    -220              -188

Chlorine          -101                       -35

Bromine           -7.2                58.8

Iodine            114                184

Melting and Boiling points increase as shown above.

NAME     COVALENT RADIUS    IONIC RADIUS

Fluorine    71                        133

Chlorine          99                          181

Bromine           114                  196

Iodine            133                 220

Size increases as shown above.

NAME            FIRST IONIZATION ENERGY

Fluorine              1681

Chlorine             1251

Bromine              1140

Iodine               1008

Ionization energy decreases as shown above.

NAME        ELECTRONEGATIVITY

Fluorine     4

Chlorine           3

Bromine           2.8

Iodine            2.5

Electronegativity decreases as shown above.

NAME      ELECTRON AFFINITY

Fluorine    -328.0

Chlorine    -349.0

Bromine    -324.6

Iodine     -295.2

Electron affinity decreases as shown above.

REACTIVITY

The reactivities of the halogens decrease. This is due to the fact that atomic radius increases in proportion with an increase of electronic energy levels. This decreases the pull for valence electrons of other atoms, minimizing reactivity.

4 0
3 years ago
HELP ME PLEASE ITS DUE 11:59 TODAY
Dmitry_Shevchenko [17]

Im sorry but its a pdf i can write on it :(

7 0
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