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3 years ago

Consider the balanced chemical equation for the combustion of methane (CH4).

Chemistry

2 answers:

Mrac [35]3 years ago

5 0

<h3>Answer:</h3>

89.6 L of O₂

<h3>Solution:</h3>

The balanced chemical equation is as,

CH₄ + 2 O₂ → CO₂ + 2 H₂O

As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,

44 g ( 1 mol) CO₂ is produced by = 44.8 L (2 mol) of O₂

So,

88 g CO₂ will be produced by = X L of O₂

Solving for X,

X = (88 g × 44.8 L) ÷ 44 g

X = 89.6 L of O₂

KIM [24]3 years ago

3 0

Took a guess and got it right!

D) 89.6 L

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