Question

Pure hexane has negligible ultraviolet absorbance above a wavelength of 200 nm. A solution prepared by dissolving 25.8 mg of benzene (C6H6, FM 78.11) in hexane and diluting to 250.0 mL had an absorption peak at 256 nm with an absorbance of 0.266 in a 1.000-cm cell. Find the molar absorptivity of benzene at this wavelength.

Answer 1

Answer:

ε = 201.5 $M^{-1} cm^{-1}$

Explanation:

Given data-

mass of benzene = 25.8 mg

= 25.8×10^-3 kg

Atomic  mass of benzene= 78.11 amu

volume of hexane = 250.00 ml = 0.2500 L

Absorbance =  0.266

Length of the cell = 1.00 cm

Hence concentration = $\frac{25.8\times10^{-3}}{78.11\times0.25 }$

solving we get

= 0.00132 M

Formula:

A= εcl

A= absorbance

c= concentration and l=  length of cell

now substituting values in the above formula

0.266= ε×0.00132×1.000

⇒ε = $\frac{0.266}{0.00132\times1.000}$

⇒ε = 201.5 $M^{-1} cm^{-1}$