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Leni [432]
3 years ago
13

When an aqueous solution of magnesium nitrate is mixed with an aqueous solution of potassium carbonate, ____________.?

Chemistry
1 answer:
spin [16.1K]3 years ago
3 0
  <span>Ca(NO3)2 + Na2CO3 = CaCO3 + 2NaNO3 
Yes a precipitate of Calcium Carbonate is formed since it is insoluble in water. 
Mol Wt of Calcium Nitrate is 164. And that of Calcium Carbonate is 100. 
One mole of Calcium Nitrate produces one mole of Calcium Carbonate. 
i.e. 164 gms will produce 100gms of precipitate 
So, 1.74gms of Calcium Carbonate will be obtained from 2.85gms Calcium Nitrate present in the original solution.</span>
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if the nuclide has a half-life of 8.0 days , what mass of the nuclide remains in the patient at 6:00 p.m. the next day? (assume
nata0808 [166]

The mass of the nuclide that will remain in the patient at 6:00 p.m. the next day is 94 g

<h3>How to determine the number of half-lives that has elapsed</h3>

We'll begin by obtaining the number of half lives that has elapsed. This can be obtained as follow:

  • Half-life (t½) = 8 days = 8 × 24 = 192 hours
  • Time (t) = 6 pm next day = 18 hours
  • Number of half-lives (n) =?

n = t / t½

n = 18 / 192

n = 0.09375

<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 100 g
  • Number of half-lives (n) = 0.09375
  • Amount remaining (N) = ?

N = N₀ / 2^n

N = 100 / (2^0.09375)

N = 94 g

Thus, 94 g of the nuclide is remaining in the patient's body,

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brainly.com/question/26374513

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4 0
2 years ago
What is 11.75 millimeters in meters
Lana71 [14]

Answer:

in meters its 0.01175

Explanation:

8 0
1 year ago
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PLS HELP QUICKLY I WILL GIVE 79 POINTS FOR YALL TO ANSWER THIS QUESTION!
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Answer:

Magnesium and strontium

Explanation:

11 protons and 11 electrons, 12 neutrons.

The atomic number of sodium is 11, therefore the number of electrons and protons are 11. The atomic mass is 23, and to find neutrons you need to subtract the atomic number from the atomic mass, therefore the number of neutrons are 12.

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A weather balloon is filled with helium that occupies a volume of 3.93 104 L at 0.995 atm and 32.0°C. After it is released, it r
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Answer: Thus the volume of the balloon at that new location is 4.65\times 10^4L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.995 atm

P_2 = final pressure of gas = 0.720 atm

V_1 = initial volume of gas = 3.93\times 10^4L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 32.0^oC=273+32.0=305.0K

T_2 = final temperature of gas = -11.7^oC=273-11.7=261.3K

Now put all the given values in the above equation, we get:

\frac{0.995\times 3.93\times 10^4}{305.0}=\frac{0.720\times V_2}{261.3}

V_2=4.65\times 10^4L

Thus the volume of the balloon at that new location is 4.65\times 10^4L

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