3 years ago

Somebody please help asap

Chemistry

2 answers:

11Alexandr11 [23.1K]3 years ago

8 0

The correct answer is Earth

Olenka [21]3 years ago

3 0

The answer to your question is Earth and also my name is juju too!!

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3 years ago

Using the average initial pH of your acetic acid solutions (2.96), and the average molarity of those solutions(.0602), calculate

Orlov [11]

Answer : The value of Ka for acetic acid is, $2.03\times 10^{-5}$

Explanation :

The chemical formula of acetic acid is, $CH_3COOH$ .

The chemical equilibrium reaction will be:

$CH_3COOH\rightleftharpoons CH_3COO^-+H^+$

Given:

pH = 2.96

First we have to calculate the concentration of hydrogen ion.

$pH=-\log [H^+]$

$2.96=-\log [H^+]$

$[H^+]=1.096\times 10^{-3}M$

That means,

$[H^+]=[CH_3COO^-]=1.096\times 10^{-3}M$

$[CH_3COOH]=0.0602-(1.096\times 10^{-3})=0.0591M$

The expression for reaction is:

$K_a=\frac{[CH_3COO^-][H^+]}{[CH_3COOH]}$

$K_a=\frac{(1.096\times 10^{-3})\times (1.096\times 10^{-3})}{0.0591}$

$K_a=2.03\times 10^{-5}$

Thus, the value of Ka for acetic acid is, $2.03\times 10^{-5}$

3 0

4 years ago

How many moles of HCl are present in 40.0 mL of a 0.035 M solution? 1. 0.0014 mol 2. 0.0060 mol 3. 0.25 mol?

Vinil7 [7]

40.0mL(1 L/1000 mL) = 0.040 L

then plug into the formula M = moles/liters 

0.035 M = moles/ 0.040L 

multipy both sides by 0.040L, and you get 0.0014 moles 

so the answer is 1

4 0

3 years ago

Somebody please help asap​

Somebody please help asap