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vichka [17]
3 years ago
6

.(09.08HC) Prove that the two circles shown below are similar.

Mathematics
1 answer:
Leni [432]3 years ago
8 0
Both circles middles are positive
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What's the answer<br><br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%20%5Ctimes%209%20%20%5Ctimes%2027%7D%20" id="TexFo
Alex777 [14]

27 Hope this helps :T

4 0
3 years ago
Read 2 more answers
Consider the graph.
Arlecino [84]

Answer:

C, f(x) = 2x + 6

Step-by-step explanation:

First, we need to plug in the values of the x coordinates and see if it matches with the y coordinate to determine if it is on the same line. Startin with 2x + 8, we have the point (1, 8) on the graph. Plugging in 1 gets you 10 for the y. This is wrong since 8 is the y coordinate. Moving on, we have 6.4(1.25)^x for the same point. Plugging in 1, we have 6.4 * 1.25 = 8, which is true. Moving on to the second point, (2, 10), we have 1.25 squared times 6.4. This is thus wrong. So, moving on to 2x + 6, we have the point (1, 8), and plugging in 1 for x, we have 8 as y. Since this satisfies the equation we move on to the next point, (2,10). Plugging in x, we have 2 * 2 + 6 = 10, which is also true. Moving on to our third point (3 , 12), we plug in 3 for x. We then get 3 * 2 + 6 = 12, which is correct. This, is our answer then.

5 0
4 years ago
Read 2 more answers
How o I get the awnser to 9s+3=57 I need help asap im in 8th grade
PIT_PIT [208]
First subtract 3 from both sides of the equal sign. 
9s + 3 = 57
      - 3     -3
9s = 54

Then divide both sides by 9.
9s = 54
/9     /9
s = 6

You can check it by plugging it back into the equation.
9s + 3 = 57
9 * 6  + 3= 57
54 + 3 = 37
57 = 57
Yep! It's correct! :)

Hope that helped. Algebra can be tricky sometimes I know but it's really just balancing equations. 
3 0
4 years ago
PLEASE HELP ME WITH THIS I NEED IT
sukhopar [10]

Answer:

1400π m³

Step-by-step explanation:

V = BH

V = 10² * π * 14 = 1400π m³

5 0
3 years ago
I need help with math the question is
velikii [3]

Answer:

P=2(S-lw)/h

Step-by-step explanation:

we have that

The formula for the surface area of the enclosed space is

S=lw+0.5Ph

Solve for P

That means ------> isolate the variable P

Subtract lw both sides

S-lw=lw+0.5Ph-lw

S-lw=0.5Ph

Multiply by 2 both sides

2(S-lw)=(2)0.5Ph

2(S-lw)=Ph

Divide by h both sides

2(S-lw)/h=Ph/h

2(S-lw)/h=P

Rewrite

P=2(S-lw)/h

7 0
3 years ago
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