The class is weighted as follows:
60% Regular Tests
10% Final Exam
15% Project
15% Homework
The total weighted points possible for the class are as follows:
(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340
To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:
(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4
So her weighted grade percent would be 285.4/340 = 83.9% which is a B.
sorry I'm in 5 grade idc what that is tho
The possible dimension of the third side is 10 units.
<h3>
What is the possible dimension of the third side?</h3>
A right triangle is a triangle that has three sides known as the opposite, adjacent and hypotenuse. The hypotenuse is the longest sides of the triangle. The opposite side is the side that faces an angle. The adjacent side is the third side.
If two side lengths are given, the third side can be determined using the Pythagoras theorem.
√a² + b ² = c
√6² + 8² = √36 + 64 = 10 units
To learn more about right angled triangle, please check: brainly.com/question/20694080
#SPJ1
Answer:
A
Step-by-step explanation:
This is because 6f+f is just 7f.
f f f f f f+f = fffffff
Soooo, ONLY A gives us 7f when added together again.
f+5f+f=7f.
f+ f f f f f +f = fffffff
Answer:
No Solutions.
Step-by-step explanation:
I will solve your system by substitution.
3y−3=3x; −3x+3y=−57
Step: Solve 3y−3=3x for y:
3y−3+3=3x+3 (Add 3 to both sides)
3y=3x+3
(3y/3=3x+3)/3
(Divide both sides by 3)
y=x+1
Step: Substitute x+1 for y in −3x+3y=−57:
−3x+3y=−57
−3x+3(x+1)=−57
3=−57 (Simplify both sides of the equation)
3+(−3)=−57+(−3) (Add -3 to both sides)
0=−60
