13/18 - 5/8 in simplest form Help!

<img src="https://tex.z-dn.net/?f=3%20%2B%20%284%20%2B%205%29%20%3D%20%283%20%2B%204%29%20%2B%20m" id="TexFormula1" title="3 + (

max2010maxim [7]

Answer:

The value of m in the expression is 5

Step-by-step explanation:

Given expression as :

3 + ( 4 + 5 ) = ( 3 + 4 ) + m

Or, 3 + ( 9 ) = ( 7 ) + m

Or, 12 = 7 + m

∴ m = 12 - 7 = 5

Hence The value of m in the expression is 5 Answer

8 0

2 years ago

Hey go to attachments and help me out- thanks very much! this is my last question for today so it would really help also stay sa

Llana [10]

Answer:

A) 250 / 8 = 31.25

31.25 x 8 = 250 Know you know that one pancake requires 31.25ml of Milk

31.25 x 4 = 125

So 4 pancakes requires 125ml of Milk

B) 5 / 8 = 0.625

0.625 x 8 = 5 So just like last time, you know that 0.625g of butter is required to make 8 pancakes

0.625 x 12 = 7.5g of Butter

So 12 pancakes requires 7.5g of butter.

Hope this makes sense !

7 0

3 years ago

Which value is equivalent to 5 + 4 x 2? A) 11 B) 13 C) 18 D) 22

Gnom [1K]

4 * 2 = 8
8 + 5 = 13
B, is the correct answer

3 0

2 years ago

Read 2 more answers

Lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. a bank conducts inter

Otrada [13]

Part A:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85

Thus, the probability that the lie detector will conclude that all 15 are telling the truth if all 15 applicants tell the truth is given by:

 $P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(15)={ ^{15}C_{15}(0.85)^{15}(0.15)^0} \\ \\ =1\times0.0874\times1=0.0874$


Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

$P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\ \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\ \\ =0.9126$

Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

$\mu=npq \\ \\ =15\times0.15\times0.85 \\ \\ =1.9125$

Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The probability that the number of truthful applicants classified as liars is greater than the mean is given by:

 $P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\ \\ 1-[P(0)+P(1)]$

 $P(1)={ ^{15}C_1(0.15)^1(0.85)^{14}} \\ \\ =15\times0.15\times0.1028=0.2312$

8 0

3 years ago

Two cables support a 800-lb weight, as shown. Find the tension in each cable.

jeka94

Answer:

892 lb (right)
653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

Rcos(45°) +Lcos(75°) = 800

Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

= 800sin(75°)/sin(120°) ≈ 892 . . . pounds

L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

(right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0

2 years ago