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Novosadov [1.4K]
2 years ago
7

Which equation is equivalent to Two-thirds x minus StartFraction 5 Over 6 EndFraction = negative StartFraction 5 Over 12 EndFrac

tion x + one-fourth?
Negative StartFraction 5 Over 6 EndFraction = one-fourth x + one-fourth
Two-thirds x = negative StartFraction 5 Over 12 EndFraction x minus StartFraction 7 Over 12 EndFraction
One-fourth x minus StartFraction 5 Over 6 EndFraction = one-fourth
Two-thirds x minus StartFraction 13 Over 12 EndFraction = negative StartFraction 5 Over 12 EndFraction x
Mathematics
2 answers:
MAVERICK [17]2 years ago
7 0

Answer:

The answer is the last one. 2/3x-13/12=-5/12x

Step-by-step explanation:

boyakko [2]2 years ago
4 0

Answer:

2/3x-13/12=-5/12x

Step-by-step explanation:

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If Croakie trains really hard, he has a new routine, 8s + 7 + s that he would like to do. If each somersault is 6 feet long, how
Vesnalui [34]

Answer:

He will go 61 feet.

Step by Step Explanation:

You fill in variables for 6 them combine your like terms.

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aleksandrvk [35]
Let's actually find the line of best fit...

m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)

m=(11*836-130*55)/(11*385-3025)

m=2046/1210  

m=93/55

b=(Σy-93Σx/55)/n

b=(55Σy-93Σx)/(55n)

b=(7150-5115)/(55*11)

b=185/55, so the line of best fit is:

y=(93x+185)/55

A)  The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.

Which means that those who do not practice at all will win about 3.36 times

B) y(13)=(93x+185)/55

y(13)≈25.34

So after 13 months of practice one would expect to win about 25.34 times.
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3 years ago
What is 150% as a fration simplest form
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3/2 would be the answer

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7 0
3 years ago
Read 2 more answers
Can someone please show me how<br><br> 19169000*e^(0.15)= 222712201<br><br> When e= 2.7182818284?
Ierofanga [76]

Answer:

It doesn't. x = 22 271 201

Step-by-step explanation:

You are going to need a calculator no matter how you do it.

x =19 169 000 \times e^{0.15}

(a) The direct method

x = 19 169 000\times 2.718 281 828^{0.15} = 19 169 000 \times 1.161 834 243 = 22 271 201

(b) The indirect method

\ln \left (19 169 000\times 2.718 281 828^{0.15} \right ) = \ln(19 169 000) + 0.15 = 16.768 805 + 0.15 = 16.918 804\\\\e^{16.918 804} = 22 271 201

8 0
3 years ago
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