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rodikova [14]
3 years ago
5

Find the Value of X. 3 8 4 6

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0
X = 4. The difference between the small and large sides on the left side is 1. (6-5=1).
You should take that difference and compare If to the size of the wheel left side, 6.

The difference should be equivalent for the other sides as well.
1:6 2:?

1:1 =2:12

2x+ 4 = 12
2x = 8
X=4
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Write the equation of a line that is perpendicular to y=-0.3x+6 and that passes through the point (3,-8)
MariettaO [177]
Hey there!

First, let's look at what perpendicular means. Imagine a cross, where there's all 90 degree angles. That's exactly what we're talking about when we say perpendicular. The given equation is in slope-intercept form, where we have:

y = mx + b
where m is the slope and b is the y-intercept.

When we're writing an equation with a perpendicular slope, we use the negative reciprocal of the given slope. Thus, we can make 0.3 1/3, and take the reciprocal to make 3, and make it negative 3 as it's the negative reciprocal. Now, we know we have a line with the slope of -3 and goes through (-3, 8). We can use the x and y values in this set of points, along with the slope, to create an equation to solve for b. That gives us:

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Now, since we have slope and y-intercept, we can write our equation as:

y = -3x + 17

Hope this helps!
5 0
3 years ago
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What is 96/126 in simplest form
Elina [12.6K]
\frac{96}{126}\\\\96\ and\ 126\ are\ even\ numbers\ divisible\ by\ 2\\\\\frac{96:2}{126:2}=\frac{48}{63}\\\\48\ and\ 63\ are\ divisible\ by\ 3,\ because\ 4+8=12(divisible\ by\ 3)\\and\ 6+3=9(divisible\ by\ 3)\\\\\frac{48:3}{63:3}=\boxed{\frac{16}{21}}\leftarrow answer
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3 years ago
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3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared
navik [9.2K]

The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get

P(t)=40

(50(1+0.05t))/(2+0.01t)=40

Cross multiply both sides, we get

50(1+0.05t)=40(2+0.01t)

Apply the distributive property a(b+c)=ab+ac, we get

50+2.5t=80+0.4t

Subtract 0.4t and 50 from both sides, we get

50+2.5t-0.4t-50=80+0.4t-0.4t-50

2.1t=30

Divide both sides with 2.1, we get

t=14.29 months

(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get

\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

Learn more about limiting factor from here brainly.com/question/18415071.

#SPJ1

8 0
2 years ago
Can u solve this question for me? 7 A and B are the questions I need. The women's soccer game prices help.
8090 [49]
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12x + 5

b) x = 3, so:

12(3) + 5 = 36 + 5 = 41

The family spent $41 to attend the game. (Ripoff)
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4 years ago
Given: g(x) = 4 - (x + 3)^2<br>find the x-intercept​
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X intercept is when the function (y) = 0.

0 = 4 - (x+3)^2

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To factor, we find what multiplies to 5 and adds to 6. In this case, it’s 5 and 1.

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x values of the intercepts are -5 and -1.
The coordinates are (-5,0) and (-1,0).
4 0
3 years ago
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