The mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.
<h3>What is the equation of the synthesis of water from hydrogen and oxygen?</h3>
The equation of the synthesis of water from hydrogen and oxygen is given as follows:
The grams of oxygen required is given below:
The equation of the combustion of propane is given as follows:
The mass of carbon dioxide produced is given below:
The equation of the reaction of copper and silver nitrate is given as follows:
Therefore, the mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.
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Answer:
0.196 M
Explanation:
First, we have to calculate the moles of sodium hydroxide.
moles = mass / molar mass
moles = 3.9280 g / (39.997 g/mol) = 0.098207 mol
It is important to realize that even though 300 mL is the volume of water firstly added to dissolve the hydroxide, the flask is then filled to the mark, meaning that the volume of the solution is 500 mL = 0.500 L.
The molar concentration of sodium hydroxide is:
The concentration is an intensive property, that is, it does not depend on the amount of matter. As a consequence, the concentration of the 50 mL of solution in the buret is the same as the concentration in the flask.
Answer:
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Answer:
Explanation:
From the question we are told that
mass of sample
volume of water
volume for extraction
partition (distribution) coefficient water
initial extraction removal
Generally the equation for the weight of sample is mathematically given by
Generally the weight extracted is therefore
is extracted with 60ml solvent .
Therefore volume of solvent (y) that would be necessary to remove an additional 7.0g