3 years ago

Is supports combustion a chemical or physical property

Chemistry

2 answers:

soldier1979 [14.2K]3 years ago

6 0

Answer:

chemical property

Explanation:

Gennadij [26K]3 years ago

4 0

Supporting combustion is a chemical property because it involves a chemical reaction that can only be reversed with another chemical reaction.

You might be interested in

The pyruvate dehydrogenase complex catalyzes the oxidative decarboxylation of pyruvate to form acetyl‑CoA. E1 , E2 , and E3 are

Nana76 [90]

It’s B Thiamine puro pyrophosphate (TPP)

4 0

3 years ago

There are three known forms of hydrogen. These forms are called (ions/copies/isotopes) of each other. Each of these forms will h

liraira [26]

Answers by order.
Isotopes.
Protons.
Neutrons.

7 0

3 years ago

Read 2 more answers

If the half-life of 37Rb is 4.7x101 years, how long would it take for 0.5 grams of a 2 gram sample to radioactively decay?

k0ka [10]

Answer: The time required will be 19.18 years

Explanation:

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

$k=\frac{0.693}{t_{1/2}}$

We are given:

$t_{1/2}=4.7\times 10^1yrs$

Putting values in above equation, we get:

$k=\frac{0.693}{4.7\times 10^1yr}=0.015yr^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.015yr^{-1}$

t = time taken for decay process = ?

$[A_o]$ = initial amount of the reactant = 2 g

[A] = amount left after decay process = (2 - 0.5) = 1.5 g

Putting values in above equation, we get:

$0.015yr^{-1}=\frac{2.303}{t}\log\frac{2}{1.5}\\\\t=19.18yrs$

Hence, the time required will be 19.18 years

4 0

3 years ago

HELP MEEEE ASAP PLEASEEEE !!!!!!!!

jasenka [17]

Ok, I will help you answer but it is very hard to read could you enlarge it first?

Thanks!

5 0

4 years ago

O2 + C3H2 + H2O + CO2 Reaction type?

Kobotan [32]

Answer:

Combustion is the reaction type if you meant to put a "=" in between C3H2 and H2O

3 0

4 years ago