<h3>
✽ - - - - - - - - - - - - - - - ~<u>
Hello There</u>
!~ - - - - - - - - - - - - - - - ✽</h3>
➷ The elements atomic number would be 91. The atomic number is simply the number of protons.
Extra info: The atomic mass would be the total of the number of protons and neutrons.
<h3><u>
✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
<span>The combined Boyle's and Charles' gas law says P1V1/T1 = P2V2/T2 </span>
<span>In this case we have (2.5 atm) (900 ml) / 298 K = (P2) (450 ml) / 336 K -----> </span>
<span>7.55 = 1.34P2 -----> P2 = 7.55 / 1.34 = 5.63 atm</span>
Molar mass :
NaBr = 103 g/mol
Pb(NO3)2 = 331.20 g/mol
<span><span /><span>Balanced chemical equation :
</span></span>2 NaBr + 1 Pb(NO3)2 = 2 NaNO3 + 1 PbBr<span>2
</span><span>
2*103 g NaBr ------------> 1 * 331.20 g Pb(NO3)2
g NaBr -------------------> 311 g Pb(NO3)2
331.20 g = 2*103*311
331.20 g = 64066
mass ( NaBr ) = 64066 / 331.20
mass ( naBr) = 193,43 g of NaBr
hope this helps!.
</span>
Answer:
k = 2.647 x 10-2 M-2 s-1
Explanation:
2NO(g) +Cl2(g) --> 2NOCl(g)
Experiment [NO] (M) [Cl2] (M) Rate (M/s)
1 0.0300 0.0100 3.4 x 10-4
2 0.0150 0.0100 8.5 x 10-5
3 0.0150 0.0400 3.4 x 10-4
Frrom experiments 1 and 3;
Reducing the concentration of NO by a factor of 2 decreases the rate of the reaction by a factor of 4. This means the reaction is second order with respect to NO.
From experiments 2 and 3:
Increasing the concentration of Cl2 by a factor of 4 increases the rate by a factor of 4. This means the reaction is first order with respect to Cl2
The rate equation is given as;
Rate = k [NO]² [Cl2]
From experiment 1;
k = [NO]² [Cl2] / Rate
k = 0.0300² * 0.0100 / 3.4 x 10-4
k = 2.647 x 10-2 M-2 s-1