Answer:
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The oxidation numbers for Nitrogen are respectively -3, +5, +4
Answer:
1 mol of CH₄ will contain greatest mass of the oxygen i.e 4 grams
Explanation:
Given;
1 mol of CH₄
0.6 mol of C₆H₆
0.4 Mol of C₃H₈.
Now,
moles = Mass / Molar mass
Thus,
for 1 mol of CH₄
1 = mass / ( 12 + 4 × (1) )
or
mass = 16 grams
now,
16 grams of CH₄ contains 4 grams of hydrogen
and, for 0.6 mol of C₆H₆
0.6 = Mass / ( 12 × 6 + 6 × 1)
or
Mass = 46.8 grams
Now,
78 grams of CH₄ contains 6 grams of hydrogen
thus,
46.8 grams of CH₄ will contain = (6 / 78) × 46.8 grams of hydrogen
or
46.8 grams of CH₄ will contain = 3.6 grams of hydrogen
and, for 0.4 Mol of C₃H₈
0.4 = mass / (3 × 12 + 8 × 1)
or
Mass of 0.4 Mol of C₃H₈ = 17.6 grams
Now,
44 grams of C₃H₈ contains 8 grams of hydrogen
thus,
17.6 grams of C₃H₈ will contain = ( 8 / 44 ) × 17.6 grams of hydrogen
or
17.6 grams of C₃H₈ will contain = 3.2 grams of hydrogen
Hence,
1 mol of CH₄ will contain greatest mass of the oxygen i.e 4 grams
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