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lorasvet [3.4K]
3 years ago
8

I need help doing this please. It’s an image

Chemistry
1 answer:
Ne4ueva [31]3 years ago
5 0

Answer:

k+

Ba2+

Al3+

K+

S2-

you may think that if it has a + it would be bigger, but it is actually the opposite.

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Which is an example of making a quantitative observation?
Elanso [62]

Answer:

A) measuring mass of metal used in a reaction

Explanation:

Quantitive observations is data involving statistics and numerical values.

4 0
3 years ago
Calculate the molarity of 65.3 grams of sugar(342.3 g/mol), c12h22011 in 750 ml of solution.
k0ka [10]

Answer:

0.254 M

Explanation:

If the formula mass of sugar is 342.3 g/mol, and there are 65.3 g, then there are 65.3/342.3=0.190768 mol.

Also, 750 mL = 0.750 L.

molarity = (moles of solute)/(liters of solution)

molarity = 0.190768/0.750 = <u>0.254</u><u> </u><u>M</u>

8 0
2 years ago
The first chemists, philosophers like, Aristotle were from which country?
qwelly [4]

Answer:

greece

Explanation:

aristole was particularly from stagria, greece. but most early philosophers are from greece

5 0
3 years ago
PLEASE HELPP<br> Will mark brainliest
zheka24 [161]

Answer:

B

Explanation:

7 0
3 years ago
A sample of a hydrocarbon is found to contain 7.48g carbon and 2.52g hydrogen. What is the empirical
Aliun [14]

Answer:

CH₄

Explanation:

To determine the empirical formula of the hydrocarbon, we need to follow a series of steps.

Step 1: Determine the mass of the compound

The mass of the compound is equal to the sum of the masses of the elements that form it.

m(CxHy) = mC + mH = 7.48 g + 2.52 g = 10.00 g

Step 2: Calculate the percent by mass of each element

%C = mC / mCxHy × 100% = 7.48 g / 10.00 g × 100% = 74.8%

%H = mH / mCxHy × 100% = 2.52 g / 10.00 g × 100% = 25.2%

Step 3: Divide each percentage by the atomic mass of the element

C: 74.8/12.01 = 6.23

H: 25.2/1.01 = 24.95

Step 4: Divide both numbers by the smallest one, i.e. 6.23

C: 6.23/6.23 = 1

H: 24.95/6.23 ≈ 4

The empirical formula of the hydrocarbon is CH₄.

6 0
3 years ago
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