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lorasvet [3.4K]
3 years ago
8

I need help doing this please. It’s an image

Chemistry
1 answer:
Ne4ueva [31]3 years ago
5 0

Answer:

k+

Ba2+

Al3+

K+

S2-

you may think that if it has a + it would be bigger, but it is actually the opposite.

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1. The attraction between the hydrogen atom in one water molecule and the oxygen molecule in another is
Rudik [331]

Answer:

d

ionic bond is formed when there is transfer of electrons and is composed of a positive cation and a negative anion

4 0
3 years ago
Consider the reactionI2(g) + Cl2(g)2ICl(g)Using standard thermodynamic data at 298K, calculate the entropy change for the surrou
Georgia [21]

We know,

\Delta H_{I_2(g)}=62.438\ KJ/mol\\\\\Delta H_{Cl_2(g)}= 0.0\ KJ/mol\\\\\Delta H_{ICl(g)}=17.78\ KJ/mol

For given reaction, I_2(g)+Cl_2(g)\ -->\ 2ICl(g)

\Delta H_{rxn}=2\Delta H_{ICl(g)}-\Delta H_{I_2(g)}-\Delta H_{Cl_2(g)}\\\\\Delta H_{rxn}=2(17.78)-0-62.438\ KJ/mol\\\\\Delta H_{rxn}=-26.878\ KJ/mol

For , 2.41 moles of I_2 :

\Delta H_{rxn}=2.41\times (-26.878)\ KJ\\\\\Delta H_{rxn}=-64.78\ KJ

We know :

\Delta S = -\dfrac{\Delta H_{rxn}}{T}\\\\\Delta S = -\dfrac{-64.78}{298}\ KJ/K\\\\\Delta S =-0.21738 \ KJ/K\\\\\Delta S=-217.38\ J/K

Hence, this is the required solution.

7 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!! DUE TOMORROW 40 POINTS!!!!!!!!!!!!!!!!!!
ollegr [7]

Answer: I believe this is the answer: The vertical columns on the periodic table are called groups or families because of their similar chemical behavior. All the members of a family of elements have the same number of valence electrons and similar chemical properties. The horizontal rows on the periodic table are called periods.

Good luck on assignment! :)

3 0
3 years ago
Read 2 more answers
Which of these is an indication that a chemical reaction has occurred?
lilavasa [31]

D. a change in color of a substance

5 0
3 years ago
Read 2 more answers
The reaction for the formation of gaseous hydrogen fluoride (HF) from molecular hydrogen (H2) and fluorine (F2) has an equilibri
mestny [16]

Answer:

[H2]eq = 0.0129 M

[F2]eq = 1.0129 M

[HF]eq = 0.9871 M

Explanation:

  • H2(g) + F2(g) ↔ 2HF(g)

∴ Ke = [HF]² / [H2]*[F2] = 1.15 E2

experiment:

∴ n H2 = 3.00 mol

∴ n F2 = 6.00 mol

∴ V sln = 3.00 L

⇒ [H2]i = 3.00 mol / 3.00 L = 1 M

⇒ [F2]i = 6.00 mol / 3.00 L = 2 M

        [ ]i    change      [ ]eq

H2     1         1 - x         1 - x

F2     2        2 - x         2 - x

HF     -            x              x

⇒ K = (x)² / (1 - x)*(2 - x) = 1.15 E2

⇒ x² / (2 - 3x + x²) = 1.15 E2 = 115

⇒ x² = (2 - 3x + x²)(115)

⇒ x² = 230 - 345x + 115x²

⇒ 0 = 230 - 345x + 114x²

⇒ x = 0.9871

equilibrium:

⇒ [H2] = 1 - x = 1 - 0.9871 = 0.0129 M

⇒ [F2] = 2 - x = 2 - 0.9871 = 1.0129 M

⇒ [HF] = x = 0.9871 M

5 0
3 years ago
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