The price of one bag of popcorn is $3.75
Step-by-step explanation:
Let,
x represent the cost of a bag of popcorn
y represent the cost of a drink.
According to given statement;
4x+12y=30 Eqn 1
x+6y=11.25 Eqn 2
Multplying Eqn 2 by 2

Subtracting Eqn 3 from Eqn 1

Dividing both sides by 2

4x+12y=30 and x+6y=11.25 can be used to find the price of one bag of popcorn and the price of one drink.
The price of one bag of popcorn is $3.75
Keywords: linear equation, elimination method
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There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
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Answer:
(x,y) becomes (-y,x) so (3,2) would become (-2,3)
Vi = 56
Vf = 56 + 7(3) = 56 + 21 = 77
THe average is (Vf + Vi)/2
(77 + 56)/2 = 133/2 = 66.5 m/s