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dmitriy555 [2]
3 years ago
15

Abstract Algebra

Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:

1.No, because inverse does not exist.

2.No, because inverse does not exist.

Step-by-step explanation:

We are given that X be  a set and let P(X) be the power set of X.

a. We have to tell P(X) with binary operation

A*B=A\cap B form  a group.

Suppose, x={1,2}

P(X)={\phi,{1},{2},{1,2}}

1.Closure  property:A\cap B\in P(X)

{1}\cap {2}=\phi \in P(X)

It is satisfied for all A,B\in P(X)

2.Associative property:(A\cap B)\cap C=A\cap (B\cap C)

If A={1},B={2},C={1,2}

A\cap(B\cap C)={1}\cap({2}\cap{1,2})={1}\cap {2}=\phi

(A\cap B)\cap C=({1}\cap{2})\cap{1,2}=\phi\cap{1,2}=\phi

Hence, P(X) satisfied the associative property.

3.Identity :A\cap B=A Where B is identity element of P(X)

A\cap X=A

It is satisfied for every element A in P(X).

Hence, X is identity element in  P(X)

4.Inverse :A\cap B=X Where B is an inverse element of A in P(x)

It can not be possible for every element that satisfied A\cap B=X

Hence, inverse does not exist.

Therefore, P(X) is not a  group w.r.t to given binary operation.

2.We have to tell P(X) with the binary operation

A*B=A\cup B form a group

Similarly,

For set X={1,2}

P(X)={\phi,{1},{2},{1,2}}

1.Closure property:If A and B are belongs to P(X) then A\cup B\in P(X) for all A and B belongs to P(X).

2.Associative property:A\cup (B\cup C)=(A\cup B)\cup C

If A={1},B={2},C{1,2}

A\cup B={1}\cup{2}={1,2}

(A\cup B)\cup C={1,2}\cup{1,2}={1,2}

B\cup C={2}\cup{1,2}={1,2}

A\cup (B\cup C)={1}\cup{1,2}={1,2}

Hence, P(X) satisfied the associative property.

3.Identity :A\cup B=A Where B is identity element of P(X)

Only \phi is that element for every A in P(X) that satisfied A\cup B=A

Hence, \phi is identity element of P(X) w.r.t union.

4.Inverse element :

A\cup B=\phi where B is  an inverse element of A in P(X)

It is not possible for every element that satisfied the property.

Hence, inverse does not exist for each element in P(X).

Therefore, P(X) is not  a group w.r.t binary operation.

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