Please help to the best of your ability .

Igoryamba

Well the square root of a number is a number times its self equaling the number you're getting the square root of. For example:

√ 25

To get sqrt of 25 we need to find a number times its self that equals 25. Lets try 8.

8 x 8 = 64

Well thats much too high, We'll try a lower number.

4 x 4 = 16

Just a little higher.

5 x 5 = 25

Since 5 times itself equals 25 that makes it the sqrt.

So, the √ 25 is 5.

7 0

3 years ago

A store owner has 17.25 lbs. of candy. If she puts the candy into 7.5 jars, how much candy will each jar contain? HELP PLEASEEE

Firdavs [7]

9.75

Step-by-step explanation:

7 0

3 years ago

2(4x+5)-2=2x+44? a.6 b.19/3 c.41/6 d.26/3

Nastasia [14]

8x+10-2= 2x+44
8x+8= 2x+44
8x-2x= 44-8
6x= 36
x= 6

so A is the correct answer :)

8 0

3 years ago

Read 2 more answers

Clare is paid $90 for 5 hours of work. At thos rate how many seconds does i take for her to earn 25 cents?

natka813 [3]

We are given

Clare is paid $90 for 5 hours of work

Total money paid =$90

total hours of work =5 hours

so, firstly we will find rate of work

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

and we get

The rate of work is

$=\frac{90}{5}$

$=18$ $/ hour

now, we have to find time for amount paid is 25 cents

so, amount paid =25 cents

100 cents =1$

so, amount paid =$ 0.25

Since, the rate is constant

so, we can take same rate here

now, we can use formula

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

$18=\frac{0.25}{T}$

now, we can solve for T

$T=\frac{0.25}{18}$ hour

since, T is in hours

so, we can change into seconds

1 hour =3600seconds

so, we can plug

$T=\frac{0.25}{18}\times 3600$ seconds

$T=50$ seconds......................Answer

6 0

3 years ago

Consider the following statement. ∀ integer d, if 6 d is an integer then d = 3. Which of the following is a negation for the sta

omeli [17]

Answer:

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

Step-by-step explanation:

If 6d is an integer, then d = 3

Let's divide the statement into two:

Let "If 6d is an integer" be p and "then d = 3" be q.

The statement is a conditional statement. Therefore, we have

p ⇒ q

The negation of p ⇒q, ¬(p ⇒ q) ≡ p ∧ ¬q

I have attached an image proving the above.

Using this: ¬(p ⇒ q) ≡ p ∧ ¬q

Then, we leave p as it is and negate q.

P is "if 6d is an integer"

q is "then d = 3," hence ¬q is "then d ≠ 3."

Therefore, the negation of "If 6d is an integer, then d = 3" is "If 6d is an integer, then d ≠ 3."

The correct option is the first:

∃ an integer d such that 6d is an integer and d ≠ 3

6 0

3 years ago