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2 years ago

Complete the slope equation of the line through (-4,8) and (4,4)

Mathematics

2 answers:

olya-2409 [2.1K]2 years ago

4 0

Answer:

-1/2

Step-by-step explanation:

We can find the slope if we are given two points

m = (y2-y1)/(x2-x1)

= (4-8)/(4 - -4)

= (4-8)/ (4+4)

= -4/8

= -1/2

Valentin [98]2 years ago

4 0

We can use the points (-4,8) and (4,4) to solve.

Slope formula: y2-y1/x2-x1

= 4-8/4-(-4)

= -4/8

= -1/2

Best of Luck!

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8 0

2 years ago

In a sample of 150 cars, 18 cars failed a safety inspection. The sampling method had a margin of error of 0.02

mestny [16]

Answer:

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

Step-by-step explanation:

Total number of cars = 150

Cars that failed the safety inspection = 18

The proportion is given by

p = 18/150

p = 0.12

p = 12%

The confidence interval is given by

p ± margin of error

Where margin of error is 0.02

0.12 ± 0.02

Lower limit = 0.12 - 0.02

Lower limit = 0.10

Lower limit = 10%

Upper limit = 0.12 + 0.02

Upper limit = 0.14

Upper limit = 14%

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

7 0

2 years ago

5x +20 and 9x. Solve for X

Dennis_Churaev [7]

If u were to add 5x+20=9x you’d get x=5

3 0

2 years ago

Find the distance between the points (-6,-2), (2,7)

Readme [11.4K]

Answer:

$d=12.0416$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Simply plug in your 2 coordinates into the distance formula to find distance <em>d</em>:

$d=\sqrt{(2-(-6))^2+(7-(-2))^2}$

$d=\sqrt{(2+6)^2+(7+2)^2}$

$d=\sqrt{(8)^2+(9)^2}$

$d=\sqrt{64+81}$

$d=\sqrt{145}$

$d=12.0416$

4 0

2 years ago

Read 2 more answers

We are interested in the dimensions of a certain rectangle. this rectangle has length twice the side of the square and width thr

Mila [183]

Area of square = s^2
Area of Rectangle = lw
l = 2s

w+3 = s
solve for w, w=s-3
Now we have l and w.
Plug both into area of rectangle formula so: (2s)(s-3)
Since both areas are equal set both equations equal to each other:
(2s)(s-3)=s^2
Now simplify
2s^2-6s=s^2
s^2-6s=0, Solve for s.
Factor polynomial. s(s-6)=0 , s can be equal to 0 or 6. HOWEVER, you cannot have a side length of 0 therefore the side length has to be 6.
Now plug in s for the length formula for the rectangle:
l = 2s so... l = 2(6) so length of rectangle = 12.
Now plug in s for the width formula for the rectangle:
w+3=s so... w+3=6 so width of rectangle = 3.
Now the dimensions of the rectangle are 12 by 3. 12 being length and 3 width.
To CHECK:
Find area of rectangle:
A=lw so A=3 times 12 so A=36
Find area of square:
We know the side is equal to 6 so
A=s^2 so 6^2 = 36
The areas are equal that verifies the answer of 12 by 3.

8 0

3 years ago