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iVinArrow [24]
4 years ago
12

Find the limit, if it exists, or type dne if it does not exist.

Mathematics
1 answer:
Phantasy [73]4 years ago
8 0
\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}

Suppose we choose a path along the x-axis, so that y=0:

\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1

On the other hand, let's consider an arbitrary line through the origin, y=kx:

\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}

The value of the limit then depends on k, which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.
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C

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3 years ago
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The value of (1-w) (1 -w^2), where w is the cube root of a complex number is
NeX [460]

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=1-1+1

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Step-by-step explanation:

at first we should multiply them with each other

then, put the value of w*3 i.e. w*3=1

then, put the value of -w-w*2 i.e. 1

then, the final answer is 1.

3 0
3 years ago
Nine hundred ninety two hundred thousandths wrote in decimal form
uranmaximum [27]

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step-by-step explanation:

3 0
2 years ago
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b

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because thats the answer

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