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kap26 [50]
3 years ago
10

For a quadratic function, which characteristics of its graph is equivalent to the zero of the function? a) y-intercept b) maximu

m point c) minimum point d) x-intercept​

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

Answer:

d) x-intercept

Step-by-step explanation:

The zeros of a function are the values of x that make y = 0.

Thus, they are the points where the graph crosses the x-axis, that is, the x-intercepts.

a) is wrong. the y-intercept is simply the value of y when x = 0.

b) and c) are wrong. A quadratic can have only one maximum or one minimum; it can't have both. And they are not zeros except in the special case of y = ±ax².

The diagram below is the graph of y = x² + 3x - 46. It shows the zeros at x = -23 and x = 20. The minimum and the y-intercept are not zeros of the function.

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Answer:

\bigg(\frac{2}{3}  {y} \bigg)^{2}

STEP BY STEP EXPLANATION

\frac{1}{4}  {x}^{2}  -  \bigg( \frac{2}{3}  \bigg)xy \\  \\  =   \bigg(\frac{1}{2}  {x} \bigg)^{2}  - 2. \bigg(\frac{1}{2}  {x} \bigg)\bigg( \frac{2}{3} y \bigg ) +  \bigg(\frac{2}{3}  {y} \bigg)^{2} \\  \\  = \bigg(\frac{1}{2}  {x}  -  \frac{2}{3} y\bigg)^{2}  \\

To make \red{\bold{\frac{1}{4}  {x}^{2}  -  \bigg( \frac{2}{3}  \bigg)xy}} a perfect square we should add \purple{\bold{\bigg(\frac{2}{3}  {y} \bigg)^{2}}}

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Please show steps to answer
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