Answer:
27 degrees
Step-by-step explanation:
The easy way is by remembering the formula (a-b)/2=c, where a is the larger angle, and b is the smallest angle. (90-36)/2=27.
The longer, more drawn out answer goes as follows. See the image to understand the notation I use:
- AOE + BOD + BOA + DOE = 360
- AOE + BOD = 90 + 36 = 126
- BOA + DOE = 360 - AOE - BOD = 234
- Since the sum of a triangle's angles is 180, ODE = (180 - DOE) / 2
- Likewise, OBA = (180 - BOA) / 2
- Since CDE is 180, CDO = 180 - ODE = 180 - (180 - DOE) / 2
- Likewise, CBA is 180, so CBO = 180 - OBA = 180 - (180 - BOA) / 2
- The interior angles of the irregular polygon CBOD add up to 360, so CBO + CDO + BOD + BCD = 360.
- Substituting what we already found, 180 - (180 - BOA)/2 + 180 - (180 - DOE)/2 + 36 + BCD = 360
- Cleaning it all up, we get 180 + (BOA + DOE)/2 + 36 + BCD = 360
- As we found in line 3, BOA + DOE = 234, so substituting that in, 180 + 117 + 36 + BCD = 360
- Finally, solving for BCD (360 - 36 - 117 - 180) we get our answer, 27
Note: The long drawn out method shown above is a way to derive the formula for the secant theorem. You do not need to use this method every time. Just remember, large angle minus small angle, all divided by 2. That is it.
Answer:
see explanation
Step-by-step explanation:
(8x - 75) and (5x) are vertically opposite angles and are congruent , then
8x - 75 = 5x ( subtract 5x from both sides )
3x - 75 = 0 ( add 75 to both sides )
3x = 75 ( divide both sides by 3 )
x = 25
Then
5x = 5(25) = 125°
8x - 75 = 8(25) - 75 = 200 - 75 = 125°
16 will go where the question mark is located
So 3/6 = 8/16
Think of it like this: if you had three slices of pizza out of 6 total, then you had half the pizza. The same goes for if you had 8 slices out of 16 total
You can use the cross multiplication rule to find x
3/6 = 8/x
3*x = 6*8
3x = 48
3x/3 = 48/3
x = 16
Answer:
0.15 or 15%
Step-by-step explanation:
Since lengths are uniformly distributed, the probability that a class period runs between a two exact times is:
![P(x_1\leq x \leq x_2)=\frac{x_2-x_1}{b-a}](https://tex.z-dn.net/?f=P%28x_1%5Cleq%20x%20%5Cleq%20x_2%29%3D%5Cfrac%7Bx_2-x_1%7D%7Bb-a%7D)
In this case, a = 47.0 and b = 52.0 minutes.
The probability that a given class period runs between 50.25 and 51.0 minutes is:
![P(50.25\leq x \leq 51.0)=\frac{51.0-50.25}{52-47} \\P(50.25\leq x \leq 51.0)=0.15=15\%](https://tex.z-dn.net/?f=P%2850.25%5Cleq%20x%20%5Cleq%2051.0%29%3D%5Cfrac%7B51.0-50.25%7D%7B52-47%7D%20%5C%5CP%2850.25%5Cleq%20x%20%5Cleq%2051.0%29%3D0.15%3D15%5C%25)
The probability is 0.15 or 15%.