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777dan777 [17]
3 years ago
13

Which of the expressions below can be factor using the difference of squares method

Mathematics
2 answers:
Alik [6]3 years ago
6 0
It would be D because both are positive and are square roots
Reika [66]3 years ago
3 0

Answer:C

Step-by-step explanation:

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Please help please !!!
Kobotan [32]
<h3>Answer:  12</h3>

========================================================

Explanation:

You can use the AAS (angle angle side) theorem to prove that triangle ABD is congruent to triangle CBD.

From there, we can then say that AD and DC are the same length

AD = DC

3y+6 = 5y-18

3y-5y = -18-6

-2y = -24

y = (-24)/(-2)

y = 12

6 0
3 years ago
What’s is the slope of the lin
Lady bird [3.3K]

Answer:

1/3

Step-by-step explanation:

<em>Method 1.</em>

slope = rise/run

Rise is vertical distance.

Run is horizontal distance.

Find two points that are easy to read (on grid intersections):

(2, -1) and (5, 0).

Start at (2, 1). You need to go to (5, 0) by moving only vertically and horizontally. Go up 1 unit. That is a rise of 1. Now go right 3 units. That is a run of 3.

rise = 1

run = 3

slope = rise/run = 1/3

<em>Method 2.</em>

Use the slope formula and two points on the line.

slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}

Use points (2, -1) and (5, 0).

slope = m = \dfrac{0 - (-1)}{5 - 2}

slope = m = \dfrac{0 + 1}{3}

slope = m = \dfrac{1}{3}

slope = 1/3

8 0
3 years ago
(5x10^10) (5x10^5) in scientific notation​
ss7ja [257]

Answer:

2.5e+16

Step-by-step explanation:

8 0
3 years ago
How to write in a single power?
nekit [7.7K]
Write what??
<em>n single power??</em>
7 0
3 years ago
Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2
ivanzaharov [21]

Answer:

اhello : tan θ = - 12/5

Step-by-step explanation:

tan θ = sin θ / cos θ .... (*)

(cosθ)² + (sinθ)² = 1   ... (**)

theta is in quadrant 2 : cosθ ≤ 0

Substitute sinθ = 12/13  into (**) and solve for cosθ :

(cosθ)² + (12/13)² = 1  

(cosθ)²  = 1   - 144/169

(cosθ)²  = 25/169

cosθ = - 5 /13  because  cosθ ≤ 0

by (*) : tan θ = (12/13)/ (-5/13) = (12/13) ×(-13/5)

tan θ = - 12/5

3 0
3 years ago
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