Write a function rule based on the table below. x f(x) 0 13 1 2 2 -9

A 12-foot ladder is placed four feet from the base of a wall.

nikitadnepr [17]

Answer:8sqrt 2 or sqrt 128

Step-by-step explanation:

We can use the Pythagorean Theorem. Since the ladder is leaning against the wall, it is the hypotenuse. It is also 4 feet away from the wall so 12^2-4^2=b^2 b^2=128 so b=8sqrt 2 or sqrt 128.

4 0

2 years ago

Please Help !!Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will

VikaD [51]

Answer:

Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40

Marie is $10 000 richer

Step-by-step explanation:

Albert

(a) $1000 at 1.2 % compounded monthly

$A = P\left(1 + \dfrac{r}{n}\right)^{nt}$

A = 1000(1 + 0.001)¹²⁰ = $1127.43

(b) $500 losing 2%

0.98 × 500 = $490

(c) $500 compounded continuously at 0.8%

$\begin{array}{rcl}A & = & Pe^{rt}\\& = & 500e^{0.008 \times 10}\\& = &\mathbf{\$541.64}\\\end{array}\\$

(d) Balance

Total = 1127.43 + 490.00+ 541.64 = $2159.07

Marie

(a) 1500 at 1.4 % compounded quarterly

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

(b) $500 gaining 4 %

1.04 × 500 = $520.00

(c) Balance

Total = 1724.99 + 520.00 = $2244.99

Hans

$2000 compounded continuously at 0.9 %

$\begin{array}{rcl}A& = &2000e^{0.009 \times 10}\\& = &\mathbf{\$2188.35}\\\end{array}\\$

Max

(a) $1000 decreasing exponentially at 0.5 % annually

A = 1000(1 - 0.005)¹⁰= $951.11

(b) $1000 at 1.8 % compounded biannually

A = 1000(1 + 0.009)²⁰ = $1196.29

(c) Balance

Total = 951.11 + 1196.29 = $2147.40

Marie is $ 10 000 richer at the end of the competition.

7 0

3 years ago

Simplify 1- cos^2 Θ / cos^2 Θ Answers sin2 θ cos2 θ tan2 θ 1

Tems11 [23]

Answer:

Trigonometric identities

$\large \begin{aligned}\cos^2 \theta + \sin^2 \theta & = 1\\\implies \quad \quad \sin^2 \theta & = 1 - \cos^2 \theta\\\\\tan \theta=\dfrac{\sin \theta}{\cos \theta} \end{aligned}$

Therefore, using the identities, the given expression can be simplified as follows:

$\large\begin{aligned}\implies \dfrac{1- \cos^2 \theta}{\cos^2 \theta} & = \dfrac{\sin^2 \theta}{\cos^2 \theta}\\\\& = \tan^2 \theta\end{aligned}$

3 0

1 year ago

Read 2 more answers

Please bro- i cant do it...

beks73 [17]

Answer:

what

Step-by-step explanation:

u cant do what???,

8 0

3 years ago

Read 2 more answers

Alonzo describes a histogram as having a cluster from 20–50, a frequency of 0 from 10–20, and a peak at 40–50. Which histogram i

Ilia_Sergeevich [38]

Answer:

A

Step-by-step explanation:

In the histogram described by the first option, the peak (18) is located at 40-50. Also, a frequency of zero is observed for range 10-20. The cluster from 20–50 means that most of the data is between this range, in fact, only 1 point is located at range 0 - 10, outside this cluster.

8 0

3 years ago

Read 2 more answers