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Vinil7 [7]
3 years ago
15

How long will it take for $4500 to grow to $25,900 at an interest rate of 7.1% if the interest is 2) compounded quarterly? round

the number of years to the nearest hundredth?

Mathematics
1 answer:
Aneli [31]3 years ago
4 0
Years = log(total / principal) / n*log(1 + rate/n)
Years = log (25,900 / 4,500) / 4 * log (1 + .071 / 4)
Years = log ( <span> <span> <span> 5.7555555556 </span> </span> </span> ) / 4 * log ( <span>1.01775)
</span>Years = 0.76008725031 / 4 * 0.0076411110514
Years = 0.76008725031 / <span> <span> <span> 0.0305644442 </span> </span> </span>
Years = <span> <span> <span> 24.8683485077 </span> </span> </span>
Years = 24.87 (rounded to nearest hundredth)

Source:
http://www.1728.org/compint3.htm


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Naily [24]
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What you can do is solve this system of equations
Let the 2 point questions = x
Let the -1 point questions = y
Let the 0 point questions = n

2x - y = 24
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2x - y = 24
2*14 - y = 24
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Now use the second equation to solve for n
14 + 4 + n = 20
18 + n = 20
n = 20 - 18
n = 2

Answer 1
<em>x = 14</em>
<em>y =  4 </em>
<em>n = 2   Total 20.</em>

This time lets try x = 15 and solve for y
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30 - y = 24
- y = - 6
y = 6 

15 + 6 + n = 20 This obviously will not work. 15 right is too many to be this circumstance. n would have to be -1 and that isn't possible.

Try x = 13
2x - y = 24
2*13 - y = 24
26 - y = 24
-y = 24 - 26
-y = -2
y = 2

Now use the second equation.
x + y + n = 20
13 + 2 + n = 20
15 +n = 20
n= 5

So Answer 2 is
<em>x = 13</em>
<em>y = 2</em>
<em>n = 5  </em>
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3 years ago
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