Remark
What you can do is solve this system of equations
Let the 2 point questions = x
Let the -1 point questions = y
Let the 0 point questions = n
2x - y = 24
x + y + n = 20 So start by letting x = 14 (just a random number) Solve the first equation.
2x - y = 24
2*14 - y = 24
28 - y = 24 Subtract 28 from both sides.
- y = 24 - 28
- y = - 4
y = 4
Now use the second equation to solve for n
14 + 4 + n = 20
18 + n = 20
n = 20 - 18
n = 2
Answer 1
<em>x = 14</em>
<em>y = 4 </em>
<em>n = 2 Total 20.</em>
This time lets try x = 15 and solve for y
2*15 - y = 24
30 - y = 24
- y = - 6
y = 6
15 + 6 + n = 20 This obviously will not work. 15 right is too many to be this circumstance. n would have to be -1 and that isn't possible.
Try x = 13
2x - y = 24
2*13 - y = 24
26 - y = 24
-y = 24 - 26
-y = -2
y = 2
Now use the second equation.
x + y + n = 20
13 + 2 + n = 20
15 +n = 20
n= 5
So Answer 2 is
<em>x = 13</em>
<em>y = 2</em>
<em>n = 5 </em>
The shape is already split into 3 different shapes, so you can find the area of each of those shapes and add them together.
Triangle 1 : 2 · 2 · .5 = 2 units²
Square : 2 · 2 = 4 units²
Triangle 2 : 4 · 2 · .5 = 4 units²
2 + 4 + 4 = 10 units²
Mark me brainlyest if i get this right 1 sec
c is what it is
Let X be a discrete random variable with geometric distribution.
Let x be the number of tests and p the probability of success in each trial, then the probability distribution is:
P (X = x) = p * (1-p) ^ (x-1). With x = (1, 2, 3 ... n).
This function measures the probability P of obtaining the first success at the x attempt.
We need to know the probability of obtaining the first success at the third trial.
Where a success is defined as a customer buying online.
The probability of success in each trial is p = 0.3.
So:
P (X = 3) = 0.3 * (1-0.3) ^ (3-1)
P (X = 3) = 0.147
The probability of obtaining the first success at the third trial is 14.7%
just plug the numbers on the graph like (2,50)