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jok3333 [9.3K]
3 years ago
8

PLS HELP IM DESPARET

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0

Answer:

19/4 or 4.75

Step-by-step explanation:

Week 1: 1 1/8 = 1.125

Week 2: -2 5/8 = -2.625*

Week 3: 1 3/4 = 1.75

Week 4: -1 1/2 = -1.5

Week 5: 2 1/8 = 2.125*

2 1/8 - (-2 5/8) = 2.125 - (-2.625)

19/4 or 4.75

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What is a function?
AleksAgata [21]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
34 in.
Troyanec [42]

Answer:

Step-by-step explanation:

Lateral surface area of the triangular prism = Perimeter of the triangular base × Height

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

(34)² = (16)² + BC²

BC = \sqrt{1156-256}

     = \sqrt{900}

     = 30 in.

Perimeter of the triangular base = AB + BC + AC

                                                      = 16 + 30 + 34

                                                      = 80 in

Lateral surface area = 80 × 22

                                  = 1760 in²

Total Surface area = Lateral surface area + 2(Surface area of the triangular base)

Surface area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height})

                                                           = \frac{1}{2}(30)(16)

                                                           = 240 in²

Total surface area = 1760 + 2(240)

                               = 1760 + 480

                               = 2240 in²

Volume = Area of the triangular base × Height

             = 240 × 20

             = 4800 in³

6 0
2 years ago
8x + 12 = 4r - 16 find r
Ber [7]
After r duhh IM SORRY
7 0
3 years ago
Read 2 more answers
PLEASE HELP QUESTION IS WORTH 16 POINTS I WILL GET AN F IF INCORRECT
Alborosie

Answer:

D)

24

Step-by-step explanation:

5 0
3 years ago
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