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grigory [225]
2 years ago
9

How many terms are in the polynomial abcd + e - fg + h^2

Mathematics
2 answers:
NikAS [45]2 years ago
8 0
This has four terms. 
Paladinen [302]2 years ago
4 0
The polynomial abcd + e - fg + h2 has four terms. 
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Plz help plz plz help helpe ​
jeka57 [31]

Answer:

-2 1/5, -1 2/5, 1/5, |-3/5|, |-1 1/5| ,|-2 2/5|

Step-by-step explanation:

Absolute value means take the positive value

-2 1/5

|-1 1/5| = 1 1/5

|-2 2/5| = 2 2/5

1/5

|-3/5| = 3/5

-1 2/5

We want the numbers from smallest to largest

The most negative is

-2 1/5, -1 2/5

Then to the fractions

1/5, |-3/5|

Then the positive numbers

|-1 1/5| ,|-2 2/5|

3 0
3 years ago
A hockey puck travels at a constant speed of 20 m/s what is the speed in miles per hour
Aleksandr [31]
YAY FREE POINTS THANKS SO MUCH!!!
4 0
3 years ago
Find the sum of the first five terms using the geometric series formula for the sequence 1/2, -1,2,-4…
sammy [17]

The sum of the first five terms is 11/2

<h3>How to determine the sum?</h3>

The series is given as:

1/2, -1,2,-4…

Calculate the common ratio of the series using

r = -4/2

Evaluate

r = -2

The sum is then calculated as:

S_n = a\frac{1 - r^n}{1 - r}

This gives

S_n = \frac{1}{2} * \frac{(1 - (-2)^5}{1 + 2}

Evaluate

S_n = \frac{1}{2} * \frac{33)}{3}

Evaluate

S_n =\frac{11}{2}

Hence, the sum of the first five terms is 11/2

Read more about series at:

brainly.com/question/11346378

#SPJ1

7 0
1 year ago
Literally noone answers my questions please help
prohojiy [21]

Answers:

  • slower train = 139 km per hour
  • faster train = 159 km per hour

=================================================

Explanation:

x = rate of the slower train

x+20 = rate of the faster train

rates are in km per hour, abbreviated as kph

The train traveling at x kph will travel 5x km after 5 hours.

Use this formula

distance = rate*time

Using that same formula, the faster train travels 5(x+20) = 5x+100 kilometers in 5 hours.

The two distances must add to 1490 if we want the trains to pass by each other. Assume that the trains are traveling on parallel side-by-side tracks.

--------------------------

So,

(slower train distance) + (faster train distance) = 1490

(5x) + (5x+100) = 1490

10x+100 = 1490

10x = 1490-100

10x = 1390

x = 1390/10

x = 139

The slower train moves at a rate of 139 km per hour.

x+20 = 139+20 = 159

The faster train moves at a speed of 159 km per hour.

--------------------------

Check:

The slower train travels 139 kph and travels for 5 hours, so it covers a distance of 139*5 = 695 km

The faster train has a speed of 159 kph and travels for 5 hours, so it covers 159*5 = 795 km

Total distance = 695+795 = 1490

The answers are confirmed.

7 0
2 years ago
Factor by using the difference of two cubes
Nikolay [14]

Answer:

Step-by-step explanation:

a) a^3-64b^3

=(a)^3-(4b)^3

=(a-4b)(a^2+4ab+16b^2)

b) 3x^3-81y^3z^6

=3(x^3-27y^3z^6)

=3{(x)^3-(3yz^2)^3}

=3(x-3yz^2)(x^2+3xyz^2+9y^2z^4)

c)16a^3b^3-54c^3d^3

=2(8a^3b^3-27c^3d^3)

=2{(2ab)^3-(3cd)^3

=2(2ab-3cd)(4a^2b^2+6abcd+9c^2d^2)

hope u got!!

6 0
3 years ago
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