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olga2289 [7]
3 years ago
14

What is the mean absolute deviation of 26 43 48 29 16 30

Mathematics
1 answer:
Serhud [2]3 years ago
8 0
The mean absolute deviation of a number set is the average distance between each value and the mean.<span> This is obtained by finding the mean of the set, determining the absolute value difference between each number, and the mean and calculating the average of these differences.
The mean of the set is ( 26 + 43 + 48 + 29 + 16 + 30 ) / 6 = 32 ;
</span> the absolute value difference between each number:
/ 26 - 32 / = 6 ; / 43 - 32 / = 11 ; / 48 - 32 / = 16 ; / 29 - 32 / = 3 ; / 16 - 32 / = 16 ;
 / 30 - 32 / = 2 ;

the mean absolute deviation of 26 43 48 29 16 30 is ( 6 + 11 + 16 + 3 + 16 + 2 ) / 6 = 9 ;
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<h2>PEMDAS (Parenthesis, exponents, multiplication, division, addition, subtraction)</h2>

Now let's solve your problems!

<h2>___________________________________________________</h2><h2>16.</h2>

First, we see if there are any parentheses. Since there are no parentheses, we will evaluate the exponent 3² first.

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