Answer:
don't know answer what is answee
Let the length of one of the shorter pieces be
. Then, we know that two of the pieces are that length, and the third piece is
. Since these are all pieces of a rope, all we need to do to figure out the lengths is add all those together, solve for
, and then plug that back in to the desired lengths:
Shorter pieces:
Longer piece:
This problem Is an example of geometrica progression. The formula
for the sum of geometric progression is:
S = a[(r^n)-1] / (r – 1)
Where s is the sum
a is the first term = 1
r is the common ratio = 2 ( because it doubles every year
n is the number of terms = (19) since the first term is when
he was born which he still 0
s = S = 1[(2^19)-1] / (2 – 1)
s = $524,287
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Can you tell me a specific name and what grade this is, Cause I have multiple ways of doing this
Answer:
it should be 2,744. i believe
Step-by-step explanation:
